K P 1. Given: KP = ST PR = TV V Prove: KR = SV Statements Reasons 1. 1. Given 2. KP + PR = ST + TV 2. 3. KP + PR =KR; ST + TV = SV 3. 4. 4. Substitution Property
K P 1. Given: KP = ST PR = TV V Prove: KR = SV Statements Reasons 1. 1. Given 2. KP + PR = ST + TV 2. 3. KP + PR =KR; ST + TV = SV 3. 4. 4. Substitution Property
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
![K
P
1.
Given: KP = ST
PR = TV
T.
V
Prove: KR = SV
Statements
Reasons
1.
1. Given
2. KP + PR = ST + TV
2.
3. KP + PR =KR; ST + TV = SV
3.
4.
4. Substitution Property](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F934fbfaf-6c69-4f0b-836e-8605b68f5540%2F17a30bcd-ccdb-4888-a576-75c483bbc491%2Fby5e6f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:K
P
1.
Given: KP = ST
PR = TV
T.
V
Prove: KR = SV
Statements
Reasons
1.
1. Given
2. KP + PR = ST + TV
2.
3. KP + PR =KR; ST + TV = SV
3.
4.
4. Substitution Property
![H
2.
Given: mZ1= m23
Prove: m/DEG=MZHEF
1
F
Statements
Reasons
1. m2l=mZ3
1.
2. m22 =m22
2.
3. mZl+mZ2=mZ3+mZ2
3.
MZDEG=m1+mZ2;
4.
MZHEF = mZ3+mZ2
4.
5. MZDEG=MZHEF
| 5.
10/18
•..](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F934fbfaf-6c69-4f0b-836e-8605b68f5540%2F17a30bcd-ccdb-4888-a576-75c483bbc491%2Fh3jhgv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:H
2.
Given: mZ1= m23
Prove: m/DEG=MZHEF
1
F
Statements
Reasons
1. m2l=mZ3
1.
2. m22 =m22
2.
3. mZl+mZ2=mZ3+mZ2
3.
MZDEG=m1+mZ2;
4.
MZHEF = mZ3+mZ2
4.
5. MZDEG=MZHEF
| 5.
10/18
•..
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