K Here are summary statistics for randomly selected weights of newborn girls: n = 36, x=3180.6 g, s= 700.5 g. Use a confidence level of 95% to complete parts (a) through (d) below. ... a. Identify the critical value to/2 used for finding the margin of error. ta/2= 2.0301 (Round to two decimal places as needed.) b. Find the margin of error. E = 237.014 g (Round to one decimal place as needed.) c. Find the confidence interval estimate of μ. 2943.58 g<μ< 3417.614 g (Round to one decimal place as needed.) d. Write a brief statement that interprets the confidence interval. Choose the correct answer below. O A. Approximately 95% of sample mean weights of newborn girls will fall between the lower bound and the upper bound. B. One has 95% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of newborn girls. OC. There is a 95% chance that the true value of the population mean weight of newborn girls will fall between the lower bound and the upper bound. OD. One has 95% confidence that the sample mean weight of newborn girls is equal to the population mean weight of newborn girls..

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Can someone please let me know if the other 3 answers are correct and could help me solve for D
K
Here are summary statistics for randomly selected weights of newborn girls: n = 36, x=3180.6 g, s = 700.5 g.
Use a confidence level of 95% to complete parts (a) through (d) below.
...
a. Identify the critical value to/2 used for finding the margin of error.
ta/2= 2.0301
(Round to two decimal places as needed.)
b. Find the margin of error.
E = 237.014 g
(Round to one decimal place as needed.)
c. Find the confidence interval estimate of μ.
2943.58 g<μ< 3417.614 g
(Round to one decimal place as needed.)
d. Write a brief statement that interprets the confidence interval. Choose the correct answer below.
O A. Approximately 95% of sample mean weights of newborn girls will fall between the lower bound and
the upper bound.
B. One has 95% confidence that the interval from the lower bound to the upper bound contains the true
value of the population mean weight of newborn girls.
OC. There is a 95% chance that the true value of the population mean weight of newborn girls will fall
between the lower bound and the upper bound.
OD. One has 95% confidence that the sample mean weight of newborn girls is equal to the population
mean weight of newborn girls..
Transcribed Image Text:K Here are summary statistics for randomly selected weights of newborn girls: n = 36, x=3180.6 g, s = 700.5 g. Use a confidence level of 95% to complete parts (a) through (d) below. ... a. Identify the critical value to/2 used for finding the margin of error. ta/2= 2.0301 (Round to two decimal places as needed.) b. Find the margin of error. E = 237.014 g (Round to one decimal place as needed.) c. Find the confidence interval estimate of μ. 2943.58 g<μ< 3417.614 g (Round to one decimal place as needed.) d. Write a brief statement that interprets the confidence interval. Choose the correct answer below. O A. Approximately 95% of sample mean weights of newborn girls will fall between the lower bound and the upper bound. B. One has 95% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of newborn girls. OC. There is a 95% chance that the true value of the population mean weight of newborn girls will fall between the lower bound and the upper bound. OD. One has 95% confidence that the sample mean weight of newborn girls is equal to the population mean weight of newborn girls..
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