k (glass) = 1.4 W/m-K, from Table A.3 k (air) = 0.0239 W/m-K, from Table A.4, property evaluated @ 270 K 1. A 0.75-m x 1.5-m window is constructed of 6-mm-thick glass. On a cold night, the inside and outside surface temperatures of the glass are 16°C and -24°C, respectively. (a) What is the rate of heat loss through the glass? (b) The window is replaced by a double-paned window, in which two panes of glass are separated by an air space. If the spacing of the panes is 13 mm and the glass surface temperatures in contact with the interior air space are 12°C and -18°C, what is the new rate of heat loss from the window? (Hint: since the temperatures on the inside glass surfaces are given, you need only analyze conduction across the air gap.)
k (glass) = 1.4 W/m-K, from Table A.3 k (air) = 0.0239 W/m-K, from Table A.4, property evaluated @ 270 K 1. A 0.75-m x 1.5-m window is constructed of 6-mm-thick glass. On a cold night, the inside and outside surface temperatures of the glass are 16°C and -24°C, respectively. (a) What is the rate of heat loss through the glass? (b) The window is replaced by a double-paned window, in which two panes of glass are separated by an air space. If the spacing of the panes is 13 mm and the glass surface temperatures in contact with the interior air space are 12°C and -18°C, what is the new rate of heat loss from the window? (Hint: since the temperatures on the inside glass surfaces are given, you need only analyze conduction across the air gap.)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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