K For a segment of a radio show, a disc jockey can play 5 records. If there are 8 records to select from, in how many ways can the program for this segment be arranged? ways ...

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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22: Answer
**Problem Statement**

For a segment of a radio show, a disc jockey can play 5 records. If there are 8 records to select from, in how many ways can the program for this segment be arranged?

**Explanation**

This problem involves calculating the number of permutations of 5 records selected from a total of 8 records. The order in which the records are played matters.

**Calculation Method**

The number of permutations of selecting 5 records from 8 can be calculated using the formula for permutations:

\[ P(n, r) = \frac{n!}{(n-r)!} \]

Where:
- \( n \) is the total number of items to choose from (8 records in this case).
- \( r \) is the number of items to choose (5 records in this case).

Substituting into the formula:

\[ P(8, 5) = \frac{8!}{(8-5)!} = \frac{8!}{3!} \]

This calculates to:

\[ P(8, 5) = \frac{8 \times 7 \times 6 \times 5 \times 4}{1} = 6720 \]

**Conclusion**

Thus, there are 6,720 different ways the program can arrange and play the 5 records out of the 8 available.

**Note:** Be sure to fill in the calculation results in the space provided if this is for an interactive element on the website.
Transcribed Image Text:**Problem Statement** For a segment of a radio show, a disc jockey can play 5 records. If there are 8 records to select from, in how many ways can the program for this segment be arranged? **Explanation** This problem involves calculating the number of permutations of 5 records selected from a total of 8 records. The order in which the records are played matters. **Calculation Method** The number of permutations of selecting 5 records from 8 can be calculated using the formula for permutations: \[ P(n, r) = \frac{n!}{(n-r)!} \] Where: - \( n \) is the total number of items to choose from (8 records in this case). - \( r \) is the number of items to choose (5 records in this case). Substituting into the formula: \[ P(8, 5) = \frac{8!}{(8-5)!} = \frac{8!}{3!} \] This calculates to: \[ P(8, 5) = \frac{8 \times 7 \times 6 \times 5 \times 4}{1} = 6720 \] **Conclusion** Thus, there are 6,720 different ways the program can arrange and play the 5 records out of the 8 available. **Note:** Be sure to fill in the calculation results in the space provided if this is for an interactive element on the website.
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