K A certain drug is used to treat asthma. In a clinical trial of the drug, 30 of 277 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 12% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. a. Is the test two-tailed, left-tailed, or right-tailed? O Two-tailed test O Right tailed test O Left-tailed test 1-Prop2Test prop <0.12 z=-0.599063924) p=0.2745651289 P-0.1083032491 n-277

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A certain drug is used to treat asthma. In a clinical trial of the drug, 30 of 277 treated subjects experienced headaches (based on data from the manufacturer). The
accompanying calculator display shows results from a test of the claim that less than 12% of treated subjects experienced headaches. Use the normal distribution as an
approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below.
a. Is the test two-tailed, left-tailed, or right-tailed?
OTwo-tailed test
Right tailed test
Left-tailed test
O
1-Prop2Test
prop <0.12
z=-0.599063924
p=0.2745651289
P-0.1083032491
n=277
Transcribed Image Text:K A certain drug is used to treat asthma. In a clinical trial of the drug, 30 of 277 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 12% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. a. Is the test two-tailed, left-tailed, or right-tailed? OTwo-tailed test Right tailed test Left-tailed test O 1-Prop2Test prop <0.12 z=-0.599063924 p=0.2745651289 P-0.1083032491 n=277
Expert Solution
Step 1

Data given

X=30, n=277 

Population proportion p=12% 

Level of significance ɑ=0.05 

 

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