Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4). 3y-3x² 2y-3x O No, because O Yes, because O Yes, because O No, because 3y-3x² 2y - 3x #0 at (2, 4) 3x²-12 3-2y 3x²-12 3-2y = 0 at (2, 4) = 0 at (2,4) #0 at (2, 4)
Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4). 3y-3x² 2y-3x O No, because O Yes, because O Yes, because O No, because 3y-3x² 2y - 3x #0 at (2, 4) 3x²-12 3-2y 3x²-12 3-2y = 0 at (2, 4) = 0 at (2,4) #0 at (2, 4)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4).
3y-3x²0 at (2,4)
2y - 3x
O No, because
O Yes, because
O Yes, because
O No, because
3y-3x²
2y - 3x
3x²-12
3-2y
3x²-12
3-2y
0 at (2, 4)
= 0 at (2,4)
0 at (2,4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9459fbbc-4853-45b5-8c0e-458b75bc654a%2F01b19ac4-5085-45e6-b8f7-72e52d8cd2f2%2F6g11h9_processed.png&w=3840&q=75)
Transcribed Image Text:Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4).
3y-3x²0 at (2,4)
2y - 3x
O No, because
O Yes, because
O Yes, because
O No, because
3y-3x²
2y - 3x
3x²-12
3-2y
3x²-12
3-2y
0 at (2, 4)
= 0 at (2,4)
0 at (2,4)
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