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Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4). 3y-3x² 2y-3x O No, because O Yes, because O Yes, because O No, because 3y-3x² 2y - 3x #0 at (2, 4) 3x²-12 3-2y 3x²-12 3-2y = 0 at (2, 4) = 0 at (2,4) #0 at (2, 4)

Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4). 3y-3x² 2y-3x O No, because O Yes, because O Yes, because O No, because 3y-3x² 2y - 3x #0 at (2, 4) 3x²-12 3-2y 3x²-12 3-2y = 0 at (2, 4) = 0 at (2,4) #0 at (2, 4)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4). 3y-3x²0 at (2,4) 2y - 3x O No, because O Yes, because O Yes, because O No, because 3y-3x² 2y - 3x 3x²-12 3-2y 3x²-12 3-2y 0 at (2, 4) = 0 at (2,4) 0 at (2,4)
Transcribed Image Text:Justify whether x³ + y² = 3xy has a horizontal tangent at (2, 4). 3y-3x²0 at (2,4) 2y - 3x O No, because O Yes, because O Yes, because O No, because 3y-3x² 2y - 3x 3x²-12 3-2y 3x²-12 3-2y 0 at (2, 4) = 0 at (2,4) 0 at (2,4)
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