Justify that 12-21-3 if x + 3, f(x) = 4 I-3 if x = 3

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Justify that ...is continuous at x = 3.

The image presents a mathematical function definition with a piecewise structure:

"Justify that 

\[ 
f(x) = 
\begin{cases} 
\frac{x^2 - 2x - 3}{x - 3} & \text{if } x \neq 3, \\
4 & \text{if } x = 3 
\end{cases} 
\]
" 

Here's an explanation of the function:

- The function \( f(x) \) is defined differently at \( x = 3 \) and at other values of \( x \).
- For \( x \neq 3 \), the function is expressed as a rational expression: \( \frac{x^2 - 2x - 3}{x - 3} \).
- For \( x = 3 \), the function has a value of 4.

This requires justification, likely involving demonstrating the function's continuity or finding a limit at \( x = 3 \).
Transcribed Image Text:The image presents a mathematical function definition with a piecewise structure: "Justify that \[ f(x) = \begin{cases} \frac{x^2 - 2x - 3}{x - 3} & \text{if } x \neq 3, \\ 4 & \text{if } x = 3 \end{cases} \] " Here's an explanation of the function: - The function \( f(x) \) is defined differently at \( x = 3 \) and at other values of \( x \). - For \( x \neq 3 \), the function is expressed as a rational expression: \( \frac{x^2 - 2x - 3}{x - 3} \). - For \( x = 3 \), the function has a value of 4. This requires justification, likely involving demonstrating the function's continuity or finding a limit at \( x = 3 \).
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