**Orbital Mechanics Problem: Shuttle Speed at Perigee****Problem Statement:**Just after launch from the earth, the space-shuttle orbiter is in the 34 x 130–mile orbit shown. At the apogee point A, its speed is 17311 mi/hr. If nothing were done to modify the orbit, what would its speed be at the perigee P? Neglect aerodynamic drag. (Note that the normal practice is to add speed at A, which raises the perigee altitude to a value that is well above the bulk of the atmosphere.) The radius of the earth is 3959 mi.**Diagram Explanation:**The diagram illustrates an elliptical orbit of the space shuttle around the Earth. The major points noted are:- **Apogee (A):** The furthest point from the Earth, where the shuttle's speed is 17311 mi/hr. This distance from the Earth's surface is given as 130 miles.- **Perigee (P):** The closest point to the Earth, with a distance of 34 miles from the Earth's surface.- **Earth:** Represented with a radius of 3959 miles.- Both distances (34 miles and 130 miles) are indicated relative to the Earth's surface.**Question:**Calculate the space-shuttle's speed \( v_P \) at the perigee point P, assuming no aerodynamic drag is present.**Answer:**\( v_P \) = _________ mi/hr

Answered: Image /qna-images/answer/68f992fe-72ea-47dd-8d83-8e0f6c04e04d.jpg

Just after launch from the earth, the space- shuttle orbiter is in the 34 x 130-mi orbit shown. At the apogee point A, its speed is 17311 mi/hr. If nothing were done to modify the orbit, what would its speed be at the perigee P? Neglect aerodynamic drag. (Note that the normal practice is to add speed at A, which raises the perigee altitude to a value that is well above the bulk of the atmosphere.) The radius of the earth is 3959 mi. 34 mi Answer: Vp mi/hr 130 mi- 17311 mi/h

Just after launch from the earth, the space- shuttle orbiter is in the 34 x 130-mi orbit shown. At the apogee point A, its speed is 17311 mi/hr. If nothing were done to modify the orbit, what would its speed be at the perigee P? Neglect aerodynamic drag. (Note that the normal practice is to add speed at A, which raises the perigee altitude to a value that is well above the bulk of the atmosphere.) The radius of the earth is 3959 mi. 34 mi Answer: Vp mi/hr 130 mi- 17311 mi/h

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

**Orbital Mechanics Problem: Shuttle Speed at Perigee**

**Problem Statement:**

Just after launch from the earth, the space-shuttle orbiter is in the 34 x 130–mile orbit shown. At the apogee point A, its speed is 17311 mi/hr. If nothing were done to modify the orbit, what would its speed be at the perigee P? Neglect aerodynamic drag. (Note that the normal practice is to add speed at A, which raises the perigee altitude to a value that is well above the bulk of the atmosphere.) The radius of the earth is 3959 mi.

**Diagram Explanation:**

The diagram illustrates an elliptical orbit of the space shuttle around the Earth. The major points noted are:
- **Apogee (A):** The furthest point from the Earth, where the shuttle's speed is 17311 mi/hr. This distance from the Earth's surface is given as 130 miles.
- **Perigee (P):** The closest point to the Earth, with a distance of 34 miles from the Earth's surface.
- **Earth:** Represented with a radius of 3959 miles.
- Both distances (34 miles and 130 miles) are indicated relative to the Earth's surface.

**Question:**

Calculate the space-shuttle's speed \( v_P \) at the perigee point P, assuming no aerodynamic drag is present.

**Answer:**

\( v_P \) = _________ mi/hr

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