Jump to level 1 CREATE TABLE Country ( Name VARCHAR (60), Population INTEGER, Over 65 PopPct FLOAT, Area DECIMAL (9, 2) DEFAULT 1.00, ISOCode2 CHAR (2) DEFAULT 'AA', ); IndepDate DATE A row is inserted into Country with Name 'Newerth' but with no other values specified. What is Newerth's Area? What is Newerth's Population? What is Newerth's ISOCode2? Ex: 5.00 or NULL Ex: 5 or NULL Ex: 'AB' or NULL

Jump to level 1 CREATE TABLE Country ( Name VARCHAR (60), Population INTEGER, Over 65 PopPct FLOAT, Area DECIMAL (9, 2) DEFAULT 1.00, ISOCode2 CHAR (2) DEFAULT 'AA', ); IndepDate DATE A row is inserted into Country with Name 'Newerth' but with no other values specified. What is Newerth's Area? What is Newerth's Population? What is Newerth's ISOCode2? Ex: 5.00 or NULL Ex: 5 or NULL Ex: 'AB' or NULL

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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O d. ALTER TABLE tableName MODIFY COLUMN columnName DATATYPE(S) What will be the result after executing this statement: SELECT SUBSTR('International', 6, 6) FROM dual? Oa tional O b. nation O c. Intern O d. national Which of the following is an exnmole of group function?
Task-6: Company also likes to find out the total purchase amount and the number of transactions made by each customer in their lifetime Create new data frame called "new-dataset", containing the columns ['CustomerlD', TotalPurchaseAmount', NumberofTransactions']. Display the last 10 rows. Expected output is as follows: CustomeriD TotalPurchaseAmount NumberofTransactions 6 15100 350.40 7 15291 328.80 15311 454.63 36 16029 3702.12 8 10 16098 430.60 12 11 16250 226.14 14 12 17420 130.85 7 13 17809 34.80 1 14 17850 725.44 45 15 18074 489.60 13
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2- selects the order line items (orderNumber, orderlinenumber) fromthe “orderdetails” table. Also, display the subtotal (quantityOrdered * priceEach) for eachline item and sorts the result set based on the subtotal descending .3- Display unique last names from employees table ordered by last name.4- Display customerNumber, customerName and creditLimit for getting the top five customerswho have the highest creditLimit.5- Find customer Name, customer country, sales representative employee number fromcustomers who do not have a sales representative.6- For each order status, display status and count of orders have this status.7- For Each order number in order details table, Display order number, sum of quantityordered (itemsCount) and sum of (priceEach * quantityOrdered) as total. With condition“total” greater than 1000.8- Display product code, product name and text description for product.9- Find customer number, customer name, order status and order number, for customerwith their orders…
numbers: 26 27 95 34 74 89 Merge(numbers, 0, 2, 5) is called. Complete the table below for leftPos and rightPos at the moment an element is copied into merged Numbers. Element copied to mergePos leftPos rightPos merged Numbers 0 0 3 26 1 Ex: 3+ 27 34 2 3 4 5 1890 74 95
Apply a data validation for the Price column that will only accept decimal input.
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Do this in MySQL please: Create a stored procedure named prc_inv_amounts to update the INV_SUBTOTAL, INV_TAX, and INV_TOTAL. The procedure takes the invoice number as a parameter. The INV_SUBTOTAL is the sum of the LINE_TOTAL amounts for the invoice, the INV_TAX is the product of the INV_SUBTOTAL and the tax rate (8 percent), and the INV_TOTAL is the sum of the INV_SUBTOTAL and the INV_TAX.
Below are some rows of the table INVOICE COD PROV_COD DATE TYPE LOC TOTAL 2910 192 2022-03-11 90 TX 1928 9301 384 2022-05-03 90 NY 2800 Overdue invoices are those whose date plus TYPE days have passed. Which of the following shows all invoices with overdue dates? a. SELECT * FROM INVOICE WHERE CURDATE() - DATE > TYPE b. SELECT * FROM INVOICE WHERE CURDATE()-TYPE >DATE c. SELECT * FROM INVOICE WHERE DATE+TYPE < CURDATE() d. SELECT * FROM INVOICE WHERE DATE+TYPE > CURDATE()
CREATE TABLE test( test_id INTEGER PRIMARY KEY, test_name varchar2 (255) ,t_date DATE, t_result varchar2(255));ALTER TABLE test ADD (t_time varchar2(1));INSERT INTO test values ('5454','corona','monday','11:15PM','positive'); (6567,'corona','sunday','10:50AM','negative');