Jump to level 1 Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a comma (no spaces). Ex: If origList = {4, 5, 10, 12) and offsetAmount = {2, 4, 7, 3), print: 6,9,17,15, 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26} const int NUM_VALS = 4; int origList [NUM_VALS]; int offset Amount [NUM_VALS]; int i; cin >> origList[0]; cin >> origList[1]; cin>> origList[2]; cin>> origList[3]; cin>> offset Amount [0]; cin>> offsetAmount [1]; cin>> offsetAmount [2]; cin >> offset Amount [3]; /* Your code goes here */ cout << endl; return 0; anner I
Jump to level 1 Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a comma (no spaces). Ex: If origList = {4, 5, 10, 12) and offsetAmount = {2, 4, 7, 3), print: 6,9,17,15, 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26} const int NUM_VALS = 4; int origList [NUM_VALS]; int offset Amount [NUM_VALS]; int i; cin >> origList[0]; cin >> origList[1]; cin>> origList[2]; cin>> origList[3]; cin>> offset Amount [0]; cin>> offsetAmount [1]; cin>> offsetAmount [2]; cin >> offset Amount [3]; /* Your code goes here */ cout << endl; return 0; anner I
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
C++
![464730.3214874 qx3zay7
Jump to level 1
Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a comma (no spaces).
Ex: If origList = {4, 5, 10, 12) and offsetAmount = {2, 4, 7, 3), print:
6,9,17,15,
1 #include <iostream>
2 #include <string.h>
3 using namespace std;
4
5
6
7
8
9
10 11 12 13 10
15
16
17
18
int main() {
19
20
21
22
23
14 cin >> origList[3];
const int NUM_VALS = 4;
int origList[NUM_VALS];
int offset Amount [NUM_VALS];
int i;
25
26}
cin >> origList[0];
>>
origList[1];
cin
cin
origList[2];
cin >> offset Amount [0];
cin >> offsetAmount [1];
cin>> offsetAmount [2];
cin>> offsetAmount [3];
/* Your code goes here */
cout << endl;
return 0;
mapanner
I
D-D-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8c67d92-2376-430d-971a-91f6c41cd4dc%2Fb0e26920-7e3a-4142-ade0-6ae0849cde2b%2F6cmacq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:464730.3214874 qx3zay7
Jump to level 1
Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a comma (no spaces).
Ex: If origList = {4, 5, 10, 12) and offsetAmount = {2, 4, 7, 3), print:
6,9,17,15,
1 #include <iostream>
2 #include <string.h>
3 using namespace std;
4
5
6
7
8
9
10 11 12 13 10
15
16
17
18
int main() {
19
20
21
22
23
14 cin >> origList[3];
const int NUM_VALS = 4;
int origList[NUM_VALS];
int offset Amount [NUM_VALS];
int i;
25
26}
cin >> origList[0];
>>
origList[1];
cin
cin
origList[2];
cin >> offset Amount [0];
cin >> offsetAmount [1];
cin>> offsetAmount [2];
cin>> offsetAmount [3];
/* Your code goes here */
cout << endl;
return 0;
mapanner
I
D-D-
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