**Julissa and Miriam's Double Slit Experiment***Julissa and Miriam are performing Young's double slit experiment. First, they use a source of light with a wavelength of λ1=500 nm, and then, with a source of light with a wavelength of λ2 = 600 nm. Which order bright fringe from the first experiment corresponds to the third dark fringe of the second experiment, if the slit spacing and distance to the screen remain the same?*---**Explanation:**In the double-slit experiment, the position of the bright and dark fringes is given by the interference pattern formed due to the overlapping of light waves. For bright fringes (constructive interference), the condition is given by:\[ d \sin \theta = m \lambda \]where:- \( d \) is the slit spacing- \( \theta \) is the angle of the fringe from the central maximum- \( m \) is the order of the fringe (m = 0, 1, 2, 3,...)- \( \lambda \) is the wavelength of the lightFor dark fringes (destructive interference), the condition is:\[ d \sin \theta = (m + 0.5) \lambda \]where \( m \) is the order of the dark fringe (m = 0, 1, 2, 3,...).To determine which order bright fringe from the first experiment corresponds to the third dark fringe of the second experiment, we can set up the equations for their positions and solve for the order of the bright fringe (\( m_1 \)) in terms of the dark fringe (\( m_2 \)) conditions:For the first experiment bright fringe:\[ d \sin \theta_{bright} = m_1 \lambda_1 \]For the second experiment third dark fringe:\[ d \sin \theta_{dark} = (2.5) \lambda_2 \]Equate the two conditions since the positions on the screen are the same:\[ m_1 \lambda_1 = (2.5) \lambda_2 \]Substituting the given wavelengths:\[ m_1 (500 \text{ nm}) = 2.5 (600 \text{ nm}) \]Solving for \( m_1 \):\[ m_1 = \frac{2.5 \times 600}{500} \]\[

Answered: Image /qna-images/answer/cda79d7b-fc26-4076-b6ae-8cbe7ec65585.jpg

Julissa and Miriam are performing Young's double slit experiment. First, they use a source of light with a wavelength of X1-500 nm, and then, with a source of ligh with a wavelength of A2 = 600 nm. Which order bright fringe from the first experiment corresponds to the third dark fringe of the second experiment, if the slit spacing and distance to the screen remain the same?

Julissa and Miriam are performing Young's double slit experiment. First, they use a source of light with a wavelength of X1-500 nm, and then, with a source of ligh with a wavelength of A2 = 600 nm. Which order bright fringe from the first experiment corresponds to the third dark fringe of the second experiment, if the slit spacing and distance to the screen remain the same?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A slit of width 0.20 mm is illuminated with monochromatic light of wavelength 480 nm, and a diffraction pattern is formed on a screen 1.0 m from the slit. a) What is the width of the central maximum? b) What are the widths of the second- and third-order maxima?
In a single-slit diffraction the angular positions of bright fringes are given by an equation sin 0 where m 0, ±1, ±2, ... a False True
In a double-slit experiment coherent light of wavelength 652 nm is incident upon two slits that are separated by 0.425 mm. The fringe pattern is viewed on a screen that is 1.69 m away. What is the distance on the screen between the first-order and second-order bright fringes? Give your answer in cm.
In a single slit diffraction experiment, the width of the slit is 3.1 x 10-5 m and the distance from the slit to the screen is 2.2 m. If the beam of light of wavelength 600 nm passes through the slit and forms a diffraction pattern on the screen, what is the linear distance on the screen from the center of the diffraction pattern to the first dark fringe? 6.3 cm 7.4 cm 4.3 cm O 8.5 cm
In a Young's double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe is 4.0 degrees. Find the ratio d/A of the slit separation d to the wavelength of the light. Number Units