Juliana had $96, which is eight times as much money as Al had. How much money did Al have? Select the correct solution method below, representing Al's money with x. O A. =96. Multiply both sides by 8. Al had $768. 8 O B. x-8 = 96. Add 8 to both sides. Al had $104. C. x+8 = 96. Subtract 8 from both sides. Al had $88. O D. 8x = 96. Divide both sides by 8. Al had $12. SUBMIT

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Juliana had $96, which is eight times as much money as Al had. How much
money did Al have? Select the correct solution method below, representing
Al's money with x.
A.
* = 96. Multiply both sides by 8. Al had $768.
8.
B. x-8 = 96. Add 8 to both sides. Al had $104.
C. x+8 = 96. Subtract 8 from both sides. All had $88.
D. 8x = 96. Divide both sides by 8. Al had $12.
SUBMIT
E PREVIOUS
DELL
Transcribed Image Text:Juliana had $96, which is eight times as much money as Al had. How much money did Al have? Select the correct solution method below, representing Al's money with x. A. * = 96. Multiply both sides by 8. Al had $768. 8. B. x-8 = 96. Add 8 to both sides. Al had $104. C. x+8 = 96. Subtract 8 from both sides. All had $88. D. 8x = 96. Divide both sides by 8. Al had $12. SUBMIT E PREVIOUS DELL
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