Juay, Apr 15 at 12:01 pm (EDT) A block of mass M-0.593kg is floating stationary in a beaker of water. A string connected to the bottom of the beaker holds the block in place. The tension in the string is 6.90 N. The bottom of the block is floating a distance h-3.59cm above the bottom of the beaker. h M T What is the magnitude and direction of the buoyant force acting on the block? 12.711 N Correct: Upward Incorrect Downward You are correct. Your receipt no. is 160-1253 Previous Tries What is the density of the block? 987kg/m^3 Submit Answer Incorrect. Tries 1/10 Previous Tries

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A Tethered Block in Water
Due this Saturday, Apr 15 at 12:01 pm (EDT)
A block of mass M=0.593kg is floating stationary in a beaker of water. A string connected to the bottom of the beaker holds the block in place. The tension in the string is 6.90 N. The bottom of the block is floating a
distance h-3.59cm above the bottom of the beaker.
h
M
What is the magnitude and direction of the buoyant force acting on the block?
12.711 N
Correct: Upward
Incorrect Downward
esc
T
You are correct.
Your receipt no. is 160-1253
What is the density of the block?
987kg/m^3
Submit Answer Incorrect. Tries 1/10 Previous Tries
This discussion is closed.
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Transcribed Image Text:A Tethered Block in Water Due this Saturday, Apr 15 at 12:01 pm (EDT) A block of mass M=0.593kg is floating stationary in a beaker of water. A string connected to the bottom of the beaker holds the block in place. The tension in the string is 6.90 N. The bottom of the block is floating a distance h-3.59cm above the bottom of the beaker. h M What is the magnitude and direction of the buoyant force acting on the block? 12.711 N Correct: Upward Incorrect Downward esc T You are correct. Your receipt no. is 160-1253 What is the density of the block? 987kg/m^3 Submit Answer Incorrect. Tries 1/10 Previous Tries This discussion is closed. I 1 ! F1 @ 2 Previous Tries F2 W # 3 80 F3 E $ 4 999 000 F4 Water R olo 5 % F5 T MacBook Air ^ 6 F6 Y & 7 F7 U * 00 8 DII FB ◄ Timer Notes Evaluate ( 1 9 DD F9 ) 0 0 4 F10 1 P Feedback Print Info (1 F11 Send Feedback + F12
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