Juanito is pulling a cart with 15.00-N force due 20.00 degrees North of West. Find a vector of equal length perpendicular to the force exerted by Juanito . Let the force exerted by Juanito be F, and the force perpendicular to that force be Fp. The vector F, makes an angle of degrees with respect to the positive x-axis. Subtracting 90 degrees from that standard angle, Fp should be due degrees north of east. Since we know that the magnitude of Fp is equal to that of Fjand we also know the angle of Fp, we can calculate the components of F p which results to: Fp=
Juanito is pulling a cart with 15.00-N force due 20.00 degrees North of West. Find a vector of equal length perpendicular to the force exerted by Juanito . Let the force exerted by Juanito be F, and the force perpendicular to that force be Fp. The vector F, makes an angle of degrees with respect to the positive x-axis. Subtracting 90 degrees from that standard angle, Fp should be due degrees north of east. Since we know that the magnitude of Fp is equal to that of Fjand we also know the angle of Fp, we can calculate the components of F p which results to: Fp=
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Juanito is pulling a cart with 15.00-N force due 20.00 degrees North of West. Find a vector of equal length
perpendicular to the force exerted by Juanito .
Let the force exerted by Juanito be F, and the force perpendicular to that force be Fp.
The vector F, makes an angle of
degrees with respect to the positive x-axis.
Subtracting 90 degrees from that standard angle, Fp should be due
degrees north
of east.
Since we know that the magnitude of Fp is equal to that of Fjand we also know the angle of Fp, we can calculate
the components of F p which results to:
Fp=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef62dfcc-5688-4af2-980c-12b5d6d24adb%2Faafa2658-0673-4374-bfc0-d60634234f94%2F62rcyil.png&w=3840&q=75)
Transcribed Image Text:Juanito is pulling a cart with 15.00-N force due 20.00 degrees North of West. Find a vector of equal length
perpendicular to the force exerted by Juanito .
Let the force exerted by Juanito be F, and the force perpendicular to that force be Fp.
The vector F, makes an angle of
degrees with respect to the positive x-axis.
Subtracting 90 degrees from that standard angle, Fp should be due
degrees north
of east.
Since we know that the magnitude of Fp is equal to that of Fjand we also know the angle of Fp, we can calculate
the components of F p which results to:
Fp=
![](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef62dfcc-5688-4af2-980c-12b5d6d24adb%2Faafa2658-0673-4374-bfc0-d60634234f94%2Fqyfnjom.jpeg&w=3840&q=75)
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