### Maximizing Profit for Blu-ray Player ProductionJuan Pablo runs a factory that manufactures Blu-ray players. The factory produces two different models: T50 and G150. Here is the breakdown of the materials and profit for each model:- **T50 model:** - Requires: - 6 ounces of plastic - 4 ounces of metal - Generates: - $19 in profit per unit- **G150 model:** - Requires: - 3 ounces of plastic - 8 ounces of metal - Generates: - $15 in profit per unitThe factory's resources are limited to:- 282 ounces of plastic- 560 ounces of metal- A maximum production capacity of 22 units of T50 each week### Problem StatementTo maximize profit, the factory needs to determine how many of each Blu-ray player model (T50 and G150) should be produced each week within the given constraints.- **Constraints:** - Plastic usage: `6x + 3y ≤ 282` - Metal usage: `4x + 8y ≤ 560` - Production limit for T50: `x ≤ 22`Here, `x` is the number of T50 units, and `y` is the number of G150 units.### Maximize ProfitThe objective is to maximize the profit function:- Total Profit = `19x + 15y`Please determine the number of each model that should be produced weekly for maximum profit and record your findings in the fields below.- **G150**:- **T50**:- **Best Profit**:

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Answered: Juan Pablo runs a factory that makes…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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