Jsing the procedure in Determination of an Equilibrium Constant, a student combines equimolar amounts of acetic acid and ethanol to react as shown by the following equation. acetic acid + ethanol = ethyl acetate + water To determine the initial concentration of acetic acid, 1.00 mL of the resulting mixture was titrated with 0.1905 M NaOH, requiring 32.50 mL What is the molarity of the acetic acid?

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Using the procedure in Determination of an Equilibrium Constant, a student combines equimolar amounts of acetic acid and ethanol to react as shown by the following equation.
acetic acid + ethanol ethyl acetate + water
To determine the initial concentration of acetic acid, 1.00 mL of the resulting mixture was titrated with 0.1905 M NaOH, requiring 32.50 mL
What is the molarity of the acetic acid?
Transcribed Image Text:Using the procedure in Determination of an Equilibrium Constant, a student combines equimolar amounts of acetic acid and ethanol to react as shown by the following equation. acetic acid + ethanol ethyl acetate + water To determine the initial concentration of acetic acid, 1.00 mL of the resulting mixture was titrated with 0.1905 M NaOH, requiring 32.50 mL What is the molarity of the acetic acid?
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