Jsing the following z-statistics, determine whether or not we can reject the correspondingnull hypotheses. Express your answers as a comparison of the z-statistics and theappropriate critical values, and state whether or not you have grounds to reject the null.z =0.25; H1: X + µg ; a = .05а.

Normal distribution is a continuous distribution that has many real-life applications. z…

Answered: Jsing the following z-statistics,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (H1) at a significance level of α=0.001. H0:μ=72.2 H1:μ≠72.2You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=7 with mean ¯x=58.1 and a standard deviation of s=14.9.What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = IncorrectWhat is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = IncorrectThe p-value is... less than (or equal to) α greater than α Correct This test statistic leads to a decision to... reject the null accept the null fail to reject the null Incorrect As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 72.2. There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 72.2. The sample data support…
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A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
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You wish to test the following claim (H.) at a significance level of a = = 0.02. H.: 41 Ha: µ1 – µ2 > 0 You obtain a sample of size ị the first population. You obtain a sample of size n2 of s2 57.2 and a standard deviation of s1 85 with a mean of 2 65 with a mean of x1 17.2 from 54.7 and a standard deviation 7.1 from the second population. You will need to determine whether or not to pool so you will use the correct df. What is the critical value for this test? Report answer accurate to three decimal places. critical value =
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You wish to test the following claim (Ha) at a significance level of a = 0.01. H₂:μ₁ = μ₂ Ha:μι > με You obtain the following two samples of data. Sample #1 Sample #2 60 50.1 91.5 89.8 56 44.8 85.6 93.4 58.4 83.8 106.9 73.9 44.8 78.1 70.8 37.7 63.5 82.7 71.7 34.7 90.6 67.7 66.8 61.6 65 65.9 77.6 61.1 111.7 106.9 51.8 88.3 69 80.5 78.1 62.6 99.7 64.5 67.2 52.6 71.2 75.3 76.2 96.8 70.8 49.2 46.1 111.7 51.8 The p-value is... mlm What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = 66.2 63.3 60 63.1 61.3 75 62.3 63.3 69.4 57.9 71.2 68.4 74.7 70.6 65.1 68.5 75.8 78.4 73.1 58.6 59.1 66 71.5 67.2 67.3 69 70.9 68.9 73.1 64.4 66.9 71.2 65.6 68.7 60.7 65.3 76.3 74.7 70.1 65.6 59.6 68.2 67.2 69.7 68.9 65.4 66.2 65.6 65.1 62.5 0.7 60.4 68.9 76.8 65.6 76.3 64.7 55.6 71.7 69.7 64.2 72.9 What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to…
Using an a = 0.05 significance level, what was the evidence for your answer to the previous question? O Because the p-value of the t-test for Experience is greater than 0.05, the analyst should not reject Ho: B₁ 0 so HA B10 is unsupported. This means that there is NO statistically significant relationship between Sales and Experience. = Because the p-value of the t-test for the Intercept is less than or equal to 0.05, the analyst should reject Ho: Bo 0 and accept HA Bo 0. This means that there is a statistically significant relationship between Sales and Experience. - O Because the p-value of the t-test for Experience is less than or equal to 0.05, the analyst should reject Ho: B1 = 0 and accept HA B1 0. This means that there is a statistically significant relationship between Sales and Experience. : O Because the p-value of the t-test for Experience is less than or equal to 0.05, the analyst should reject Ho: B1 = 0 and accept HA B1 0. This means that there is NO statistically…
Please solve for p value ,determine weather to reject hypothesis and state the conclusion for enough evidence
You wish to test the following claim (Ha) at a significance level of a = 0.02. For the context of this problem, 44 = PostTest - PreTest where the first data set represents a pre-test and the second data set represents a post-test. (Each row represents the pre and post test scores for an individual. Be careful when you enter your data and specify what your 4i and u2 are so that the differences are computed correctly.) H.:Hd = 0 0 + Prl : "H You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: pre-test post-test 44.8 52.3 47.6 44.1 56.6 51.2 50.4 54.8 55.4 58.9 38 44.1 32.1 36 41.7 52.6 36.9 45.9 50.8 55 52.5 65.8 35.7 38.5 39.3 30.8 36.4 33.4 53.7 60 What is the test statistic for this sample? test statistic = (Report answer accurate to 4 decimal places.) What is the p-value for this sample? p-value = (Report answer accurate to 4 decimal places.) The p-value is... O less than (or…

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Jsing the following z-statistics, determine whether or not we can reject the corresponding null hypotheses. Express your answers as a comparison of the z-statistics and the appropriate critical values, and state whether or not you have grounds to reject the null. z = 0.25; H1: X + µg ; a = .05 а.