Josh wants to convince his mother to stop buying single-ply toilet paper. Josh believes that even though Fluffy, a two-ply toilet paper costs more, it will last longer because it is more absorbent. To help substantiate his claim, Josh performed a study. He purchased a random sample of 18 rolls of Fluffy. For each roll, he determined how many squares are needed to completely absorb one-quarter cup of water. Here is a dotplot of the data. The mean of the sample is 24.444 squares with a standard deviation of 2.45 squares. Single-ply toilet paper requires 26 squares to absorb one-quarter cup of water. Josh would like to carry out a test to determine if there is convincing evidence that the mean number of squares of Fluffy that are needed to absorb one-quarter cup of water is fewer than 26 squares. What is the appropriate test statistic and P-value of this test? (A) z = -2.69z=−2.69, PP-value = 0.0036=0.0036 (B) t = -2.69t=−2.69, PP-value = 0.0078=0.0078 (C) t = -2.69t=−2.69, PP-value = 0.0156=0.0156 (D) t = 2.69t=2.69, PP-value = 0.9922=0.9922 (E) z = 2.69z=2.69, PP-value = 0.9964=0.9964

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ISBN:9781119256830
Author:Amos Gilat
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Josh wants to convince his mother to stop buying single-ply toilet paper. Josh believes that even though Fluffy, a two-ply toilet paper costs more, it will last longer because it is more absorbent. To help substantiate his claim, Josh performed a study. He purchased a random sample of 18 rolls of Fluffy. For each roll, he determined how many squares are needed to completely absorb one-quarter cup of water. Here is a dotplot of the data.

The mean of the sample is 24.444 squares with a standard deviation of 2.45 squares. Single-ply toilet paper requires 26 squares to absorb one-quarter cup of water. Josh would like to carry out a test to determine if there is convincing evidence that the mean number of squares of Fluffy that are needed to absorb one-quarter cup of water is fewer than 26 squares. What is the appropriate test statistic and P-value of this test?

  • (A) z = -2.69z=−2.69, PP-value = 0.0036=0.0036
  • (B) t = -2.69t=−2.69, PP-value = 0.0078=0.0078
  • (C) t = -2.69t=−2.69, PP-value = 0.0156=0.0156
  • (D) t = 2.69t=2.69, PP-value = 0.9922=0.9922
  • (E) z = 2.69z=2.69, PP-value = 0.9964=0.9964
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