John has alkaptonuria; it "runs in the family". John and his grandmother are both homozygous for alkaptonuria. John's grandmotherhas two brothers and a sister. One of the brothers had alkaptonuria and his daughter is John's mother. Based on this information,John's parents are:

Since alkaptonuria is a genetic disorder that is inherited in an autosomal recessive manner, John…

Answered: John has alkaptonuria; it "runs in the…

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section10.7: Defects In Transport Proteins: Hemoglobin

Problem 2EG

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Similar questions

What are the chances that Ann and Michael next child will have the disease. Assume people marrying into the family are homozygous normal.
What is the little girl's blood type?
Jane has type O blood. Her child has type O blood. George's blood type is homozygous B. Could George be the father of Jane's baby?
Cystic fibrosis (CF) is an autosomal recessive trait (a). Assume that Emily (who has CF) decides to have children with a man who does not have CF and who is not a carrier of CF. What are their genotypes, and what is the probability that they will have a child who is a carrier for CF?
Complete the punnett square for the following:Matt has blood type B and is heterozygous. Sue has blood type A and is heterozygous.
Alfred is heterozygous for tongue rolling and has five fingers. Alfreda, his wife, cannot roll her tongue and is heterozygous for polydactyly. Use R/r for tounge rolling, P/p for polydactyly. What is Alfred’s genotype? ____________ What is Alfreda’s genotype? ____________
Mark has an autosomal recessive condition called sickle cell anemia, a serious blood disorder that is associated with painful complications. His spouse has not experienced symptoms of sickle cell anemia but their first child developed the disease. What conclusions can be drawn about the mother's genotype and the probability of having a second child with the condition? Answer Choices: A: her genotype is heterozygous and there is a 25% percent chance of having another child with the disorder B: her genotype is heterozygous and there is a 50% percent chance of having another child with the disorder C: her genotype is heterozygous and there is a 75% percent chance of having another child with the disorder D: she lacks the allele for sickle cell anemia in that she lacks symptoms of the disease. There is a 0% percent chance of having another child with the disorderMark has an autosomal recessive condition called sickle cell anemia, a serious blood disorder that is associated with…
A couple who are a carrier of sickle-cell disease with blood type A for the female and type B for the male (assume heterozygosity for blood types). What is the probability that they will have a son with blood type B and is sickle- cell? Please show the solution.
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John has unattached earlobes (dominant) like his father, but his mother has attached earlobes (recessive). What is John’s genotype? Show punnet square
Parents Genotype : Bb/bb – Eye Color - (brown eyes dominant , blue eyes recessive) Dd- Dimples ( dominant) Cc/cc- Cleft chin (Dominant) Sarah BbDdcc James bbDdCc If they plan to have 4 children, what is the probability of having: a) all girls with blue eyes and dimples b) 2 children with dimples
Tom and Jane have four children: two girls, Jill and Janet, and two boys, Tim and Todd. Tim has a genetic disorder that gives him polka dotted finger nails, but Todd Jill and Janet do not. All four of the children get married (to people outside their family) and have children. Here are the results: Jill’s ChildrenJack affected with polka dot finger nailsJacob NOT affected with polka dot finger nailsJohn affected with polka dot finger nails Janet’s ChildrenJason NOT affected with polka dot finger nailsJustin affected with polka dot finger nailsJessica NOT affected with polka dot finger nails Tim and Todd have NO children affect with polka dot finger nails This genetic disorder is mostly likely: Group of answer choices 1 Autosomal Recessive 2 X-linked recessive 3 X-linked dominant 4 Y-linked 5 Autosomal Dominant

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John has alkaptonuria; it "runs in the family". John and his grandmother are both homozygous for alkaptonuria. John's grandmother has two brothers and a sister. One of the brothers had alkaptonuria and his daughter is John's mother. Based on this information, John's parents are: