Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $22,900, and the 5th year his income was $26,100. In which year was his income S29,300? His income was $29,300 in the th year.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $22,900, and the 5th year his income was $26,100. In which year was his income $29,300?
His income was $29,300 in the th year.
Transcribed Image Text:Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $22,900, and the 5th year his income was $26,100. In which year was his income $29,300? His income was $29,300 in the th year.
Expert Solution
Step 1

Given: Joe's income in the first year is $22,900, and in the fifth year his income was $26,100.

Since Joe's income increases by the same dollar amount every year, therefore it follows an arithmetic progression(A.P) with the first term as 22,900(a), and the fifth term as $26100(a5).

Let the common difference of this A.P be d. Then,

an=a+n-1da5=a+5-1d=a+4d26100=22900+4d4d=3200d=800

So the common difference of given A.P is 800.

 

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