Joan was convinced that students who study abroad during college would report a more positive “college experience” than the general population of students, whose average “college experience” is m = 4.5 on a scale ranging from 1, totally negative, to 7, extremely positive). She sampled 7 students who had studied abroad. Their scores are as follows:X4677657 *For this problem, you will be conducting a t test for a single sample. See pages 235-237 for an example of conducting this type of analysis and model your response after that problem) Step 3: What is the critical value for this test at alpha = .05 (i.e., significance level of 5%)?

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Description: Joan was convinced that students who study abroad during college would report a more positive “college experience” than the general population of students, whose average “college experience” is m = 4.5 on a scale ranging from 1, totally negative, to

Hypothesis: Null hypothesis: H0: μ=4.5Alternative hypothesis: H1: μ>4.5 Step-by-step procedure to…

Answered: Joan was convinced that students who…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Joan was convinced that students who study abroad during college would report a more positive “college experience” than the general population of students, whose average “college experience” is m = 4.5 on a scale ranging from 1, totally negative, to 7, extremely positive). She sampled 7 students who had studied abroad. Their scores are as follows:

*For this problem, you will be conducting a t test for a single sample. See pages 235-237 for an example of conducting this type of analysis and model your response after that problem

) Step 3: What is the critical value for this test at alpha = .05 (i.e., significance level of 5%)?

Expert Solution

Step 1

Hypothesis:

$\begin{array}{rcl} Null hypothesis : H_{0} : μ & = & 4.5 \\ Alternative hypothesis : H_{1} : μ & > & 4.5 \end{array}$

Step-by-step procedure to obtain the mean and the standard deviation using Excel is given below:

In Excel sheet, enter Scores X in one column.
In Data, select Data Analysis and choose Descriptive statistics.
In Input Variable Range, select Scores X.
Select Summary Statistics.
Click Labels.
Click Ok.

Output obtained using the Excel is given below:

From the output, the sample mean is 6 and standard deviation is 1.15.

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