Jiven the following iermochemičál đătă ăt 298 - NH3 (g) + 5 O2 (g) 4 NO (g) + 6 H2O (1) AH° = -1170 kJ mol- NO (g) + O2 (g) = 2 NO2 (g) AH° = –114 kJ mol-! NO2 (g) + H2O (1) = 2 HNO3 (1) + NO (g) AH° = -72 kJ mol-' find AH° at 298 K for the following reaction without using tabulated thermochemical data: NH3 (g) +2 O2 (g) = HNO; (1) + H2O (1) -414 kJ mol-1
Jiven the following iermochemičál đătă ăt 298 - NH3 (g) + 5 O2 (g) 4 NO (g) + 6 H2O (1) AH° = -1170 kJ mol- NO (g) + O2 (g) = 2 NO2 (g) AH° = –114 kJ mol-! NO2 (g) + H2O (1) = 2 HNO3 (1) + NO (g) AH° = -72 kJ mol-' find AH° at 298 K for the following reaction without using tabulated thermochemical data: NH3 (g) +2 O2 (g) = HNO; (1) + H2O (1) -414 kJ mol-1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How did it become -414 kJ mol-1? I can't figure out without using the data. Thank you
![Given the following thermochemical data at 298 K:
4 NH3 (g) + 5 O2 (g) = 4 NO (g) + 6 H2O (1)
AH° = -1170 kJ mol-'
2 NO (g) + O2 (g) = 2 NO2 (g)
AH° = -114 kJ mol-
3 NO2 (g) + H2O (1) = 2 HNO3 (1) + NO (g)
AH° = -72 kJ mol-
find AH° at 298 K for the following reaction without using tabulated thermochemical data:
NH3 (g) +2 O2 (g) = HNO3 (1) + H2O (1)
[-414 kJ mol·']](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdde82184-2f4f-4ef1-9b9e-a15481f1eeaf%2F4c2d4648-00a7-49e7-be5d-a37a4f3952f7%2Fs31a6b_processed.png&w=3840&q=75)
Transcribed Image Text:Given the following thermochemical data at 298 K:
4 NH3 (g) + 5 O2 (g) = 4 NO (g) + 6 H2O (1)
AH° = -1170 kJ mol-'
2 NO (g) + O2 (g) = 2 NO2 (g)
AH° = -114 kJ mol-
3 NO2 (g) + H2O (1) = 2 HNO3 (1) + NO (g)
AH° = -72 kJ mol-
find AH° at 298 K for the following reaction without using tabulated thermochemical data:
NH3 (g) +2 O2 (g) = HNO3 (1) + H2O (1)
[-414 kJ mol·']
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