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JE Take the curl of V x H = &- at yields VX(V x E) = V X (-μ OH dt This is the wave equation for E. In an entirely similar way, we can obtain According to (2.2.3) where V-E = 0, we can obtain -) = -μ V2E - με Using the vector identity curl of curl Vx (V x A) = V(V-A) - V²A, (2.3) becomes VxVxE=V (VE) - V²E {2H – με 02E at² (VxH) öt 0²H 01² = 0 = 0 - με TRY FOR YOURSELF! ²E Jt² (2.3) (2.4) (2.5) (2.6) 6

JE Take the curl of V x H = &- at yields VX(V x E) = V X (-μ OH dt This is the wave equation for E. In an entirely similar way, we can obtain According to (2.2.3) where V-E = 0, we can obtain -) = -μ V2E - με Using the vector identity curl of curl Vx (V x A) = V(V-A) - V²A, (2.3) becomes VxVxE=V (VE) - V²E {2H – με 02E at² (VxH) öt 0²H 01² = 0 = 0 - με TRY FOR YOURSELF! ²E Jt² (2.3) (2.4) (2.5) (2.6) 6

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Explain what the symbols are and how they got the bottom equation
JE Take the curl of V x H = &- at yields VX(V x E) = V X (-μ OH ot This is the wave equation for E. In an entirely similar way, we can obtain According to (2.2.3) where V-E = 0, we can obtain -) = −μ p2E - με Using the vector identity curl of curl Vx (V x A) = V(VA) - V²A, (2.3) becomes VxVxE=V (VE) - V²E {2H – με 02E at² (VxH) öt 0²H 01² = 0 = 0 =-μE TRY FOR YOURSELF! ²E Jt² (2.3) (2.4) (2.5) (2.6) 6
Transcribed Image Text:JE Take the curl of V x H = &- at yields VX(V x E) = V X (-μ OH ot This is the wave equation for E. In an entirely similar way, we can obtain According to (2.2.3) where V-E = 0, we can obtain -) = −μ p2E - με Using the vector identity curl of curl Vx (V x A) = V(VA) - V²A, (2.3) becomes VxVxE=V (VE) - V²E {2H – με 02E at² (VxH) öt 0²H 01² = 0 = 0 =-μE TRY FOR YOURSELF! ²E Jt² (2.3) (2.4) (2.5) (2.6) 6
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