Je-2x sin 2x dx

Q: 1 + tan² dx

A:

Q: 6 ブ snx dx=

A: We can make it easier for you.

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A:

Q: sec4 dx

A: The integral is . Let . Differentiating both sides.

Q: S(1 + sinx)-1sinxdx

A:

Q: se*cosx dx e-sinx

A: Let sinx = u then cosxdx = du

Q: ýt 29-ty-osinx

A:

Q: sin 3x dx 3-10cos3x 10.

A:

Q: tan-13x dx 1 + 9x2

A:

Q: s coszy -sinzy)du

A: To find, ∫cos 2x - sin 2x2 dx

Q: integrate sin2x/sin5x.sin3x

A: To integrate: ∫sin2xsin5xsin3xdx Solution: We know, sin(A-B)=sinAcosB-cosAsinB    ...(1)…

Q: | sech²xtanh²x dx

A: We can find the integration as below

Q: cotxy5+tanx dx cotx-sinxcosx

A: Since you have asked multiple questions in a single request, we will be answering only the 1st…

Q: Ja (1 – sinx)3/2 (1+ sinx)²dx"

A: If , then the independent variable x is called the input of the function and the dependent variable…

Q: Sin2A =

A: The detailed solution is given below Thank you

Q: Stan³ x secx dx

A:

Q: Find 6x2 sin x3 dx

A:

Q: dx sec5x(3+sin5х)

A: