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JCL(input) aue to the input coupling capacitor C,? O Vcc +15 V Rc 3.9 kn C3 Rh RR2(Br. + RE1)) + Rs R1 68 k2 %3D r=50 0.33 иF R1 5.6 kN B=100 R, 50 2 0.33 дF REI 100 R 22 k RE2 1.5k 50 mVpp 100 F fcl(input) 200 Hz

JCL(input) aue to the input coupling capacitor C,? O Vcc +15 V Rc 3.9 kn C3 Rh RR2(Br. + RE1)) + Rs R1 68 k2 %3D r=50 0.33 иF R1 5.6 kN B=100 R, 50 2 0.33 дF REI 100 R 22 k RE2 1.5k 50 mVpp 100 F fcl(input) 200 Hz

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Calculate the low cutoff frequency fcLlinput) due to the input coupling capacitor C? VcC +15 V Rc 3.9 k2 C3 R1 68 k2 out Rh RR2||(BG, + Rei)) + R$ %3D in r=50 0.33 uF RL B=100 5.6 k2 R, 0.33 uF REL 50 2 100 R2 22 k2 RE2 1.5 kN 100 µF 50 mVpp fcl(input) = 200 Hz
Transcribed Image Text:Calculate the low cutoff frequency fcLlinput) due to the input coupling capacitor C? VcC +15 V Rc 3.9 k2 C3 R1 68 k2 out Rh RR2||(BG, + Rei)) + R$ %3D in r=50 0.33 uF RL B=100 5.6 k2 R, 0.33 uF REL 50 2 100 R2 22 k2 RE2 1.5 kN 100 µF 50 mVpp fcl(input) = 200 Hz
RE2 1.5 kN C2 100 μF 22 kN 50 mVpp O felinput) = 200 Hz fcllinput) = 350 Hz fcl(input) = 450 Hz fcl(input) = 150 Hz 두 두
Transcribed Image Text:RE2 1.5 kN C2 100 μF 22 kN 50 mVpp O felinput) = 200 Hz fcllinput) = 350 Hz fcl(input) = 450 Hz fcl(input) = 150 Hz 두 두
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