Japan's high population density has resulted in a multitude of resource-usage problems. One especially serious difficulty concerns waste removal. The article "Innovative Sludge Handling Through Pelletization Thickening"t reported the development of a new compression machine for processing sewage sludge. An important part of the investigation involved relating the moisture content of compressed pellets (y, in %) to the machine's filtration rate (x, in kg-DS/m/hr). Consider the following data. * 125.5 98.0 201.6 147.4 145.9 124.9 112.1 120.2 161.0 178.9 y 77.9 76.6 81.3 79.9 78.2 78.2 77.3 76.8 80.1 80.3 x 159.3 145.7 75.2 151.4 144.3 125.0 198.9 132.7 159.4 110.6 y 80.1 79.1 76.9 78.0 79.6 78.0 81.5 76.9 78.9 78.7 Relevant summary quantities are x; = 2818.0 Ty; = 1574.3, x = 415,991.74, xy, = 222,594.63, y? = 123.963.13. Also, x = 140.900, y = 78.72, S = 18,935.5400, s = 775.760, and SSE = 10.300. The estimated standard deviation is G = 0.756 and the equation of the least squares line is y = 72.938 + 0.041x. Consider the filtration rate-moisture content data introduced above. (a) Compute a 90% CI for B, + 1256,, true average moisture content when the filtration rate is 125. (Round your answers to three decimal places.) (b) Predict the value of moisture content for a single experimental run in which the filtration rate is 125 using a 90% prediction level. (Round your answers to three decimal places.) How does this interval compare to the interval of part (a)? Why is this the case? The width of the confidence interval in part (a) is ---Select-- v the width of the prediction interval in part (b) since the -Select--- v interval must account for both the uncertainty in knowing the value of the population mean in addition to the data scatter. (c) How would the intervals of parts (a) and (b) compare to a CI and PI when filtration rate is 115? Answer without actually calculating these new intervals. Because the value of 115, denoted by x", is ---Select--- Vx than 125, the term (x* - x) will be ---Select--- V, making the standard error --Select-- V, and thus the width of the interval is -Select--- ♥

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Question

2

Japan's high population density has resulted in a multitude of resource-usage problems. One especially serious difficulty concerns waste removal. The article "Innovative Sludge Handling Through Pelletization Thickening"t reported the
development of a new compression machine for processing sewage sludge. An important part of the investigation involved relating the moisture content of compressed pellets (y, in %) to the machine's filtration rate (x, in kg-DS/m/hr).
Consider the following data.
125.5 98.0 201.6
147.4 145.9
124.9 112.1 120.2 161.0 178.9
y
77.9 76.6
81.3
79.9
78.2
78.2
77.3
76.8
80.1
80.3
x 159.3 145.7
75.2
151.4
144.3
125.0 198.9
132.7
159.4 110.6
y
80.1
79.1 76.9
78.0
79.6
78.0
81.5
76.9
78.9 78.7
Relevant summary quantities are x; = 2818.0 y; = 1574.3, x = 415,991.74, xy; = 222,594.63, Sy? = 123,963.13. Also, x = 140.900, y = 78.72, S = 775.760, and SSE = 10.300. The estimated
= 18,935.5400, S,
standard deviation is o = 0.756 and the equation of the least squares line is y = 72.938 + 0.041x.
Consider the filtration rate-moisture content data introduced above.
(a) Compute a 90% CI for Bo + 1256,, true average moisture content when the filtration rate is 125. (Round your answers to three decimal places.)
(b) Predict the value of moisture content for a single experimental run in which the filtration rate is 125 using a 90% prediction level. (Round your answers to three decimal places.)
How does this interval compare to the interval of part (a)? Why is this the case?
The width of the confidence interval in part (a) is ---Select-- v the width of the prediction interval in part (b) since the
addition to the data scatter.
--Select--- V interval must account for both the uncertainty in knowing the value of the population mean in
(c) How would the intervals of parts (a) and (b) compare to a CI and PI when filtration rate is 115? Answer without actually calculating these new intervals.
Because the value of 115, denoted by x*, is ---Select---
vx than 125, the term (x* - x)2 will be --Select--- V,
, making the standard error --elect--- V
and thus the width of the interval is ---Select--- V
(d) Interpret the hypotheses Ho: Bo + 1258, = 80 and H: Bo + 1258, < 80.
Assuming the filtration rate is 125 kg-DS/m/h, we would test to see if the average moisture content of the compressed pellets is -Select---
80%.
Carry out a hypothesis test at significance level 0.01.
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)
t =
P-value =
Transcribed Image Text:Japan's high population density has resulted in a multitude of resource-usage problems. One especially serious difficulty concerns waste removal. The article "Innovative Sludge Handling Through Pelletization Thickening"t reported the development of a new compression machine for processing sewage sludge. An important part of the investigation involved relating the moisture content of compressed pellets (y, in %) to the machine's filtration rate (x, in kg-DS/m/hr). Consider the following data. 125.5 98.0 201.6 147.4 145.9 124.9 112.1 120.2 161.0 178.9 y 77.9 76.6 81.3 79.9 78.2 78.2 77.3 76.8 80.1 80.3 x 159.3 145.7 75.2 151.4 144.3 125.0 198.9 132.7 159.4 110.6 y 80.1 79.1 76.9 78.0 79.6 78.0 81.5 76.9 78.9 78.7 Relevant summary quantities are x; = 2818.0 y; = 1574.3, x = 415,991.74, xy; = 222,594.63, Sy? = 123,963.13. Also, x = 140.900, y = 78.72, S = 775.760, and SSE = 10.300. The estimated = 18,935.5400, S, standard deviation is o = 0.756 and the equation of the least squares line is y = 72.938 + 0.041x. Consider the filtration rate-moisture content data introduced above. (a) Compute a 90% CI for Bo + 1256,, true average moisture content when the filtration rate is 125. (Round your answers to three decimal places.) (b) Predict the value of moisture content for a single experimental run in which the filtration rate is 125 using a 90% prediction level. (Round your answers to three decimal places.) How does this interval compare to the interval of part (a)? Why is this the case? The width of the confidence interval in part (a) is ---Select-- v the width of the prediction interval in part (b) since the addition to the data scatter. --Select--- V interval must account for both the uncertainty in knowing the value of the population mean in (c) How would the intervals of parts (a) and (b) compare to a CI and PI when filtration rate is 115? Answer without actually calculating these new intervals. Because the value of 115, denoted by x*, is ---Select--- vx than 125, the term (x* - x)2 will be --Select--- V, , making the standard error --elect--- V and thus the width of the interval is ---Select--- V (d) Interpret the hypotheses Ho: Bo + 1258, = 80 and H: Bo + 1258, < 80. Assuming the filtration rate is 125 kg-DS/m/h, we would test to see if the average moisture content of the compressed pellets is -Select--- 80%. Carry out a hypothesis test at significance level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value =
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON