James placed a $25 bet on a red and a $5 bet on the number 33 (which is black) on a standard 00 roulette wheel.   -if the ball lands in a red space, he wins $25 on his 'red' but loses $5  on his '33' bet - so he wins $20 -if the ball lands the number 33, he loses $25 on his 'red' bet but wins $175 on his '33' bet: He wins $150 -if the ball lands on a spae that isn't red and isnt 33 he loses both bets, so he loses $30 So for each spin; he either wins $150, wins $20, or loses $30 -probability that he wins $150 is 1/38 or .0263 -probability that he wins $20 is 18/38 or .4737 -probability that he loses $30 is 19/38 or .5000   let X = the profit that james makes on the next spin x P (X=x) x*P(X=x) x^2*P(X=x) 150 .0263 3.945 591.75 20 .4737 9.474 189.48 -30 .5000 -15.000 450.00 sum (sigma) 1.000 -1.581 1231.23   u (expected value)= -$1.581 variance = 1228.73044 standard deviation = 35.053   FILL IN THE BLANK   if you play 2500 times, and Let, x (x bar)= the mean winnings (or loses) per game. The expected value of x, called ux (expected value of x bar) is ________________________   The standard deviation of x (x bar), called 0x (standard deviation of x bar)  is _____________________________   this means that for 2500 games, you expect your winnings (or loss) to be 2500 times your average loss per game, which is _____________________.   Multiplying the value found for 0x (standard deviation of X (x bar)) by  2500 (the number of games) we find that standard deviation in profit for 2500 games is _________________

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James placed a $25 bet on a red and a $5 bet on the number 33 (which is black) on a standard 00 roulette wheel.

 

-if the ball lands in a red space, he wins $25 on his 'red' but loses $5  on his '33' bet - so he wins $20

-if the ball lands the number 33, he loses $25 on his 'red' bet but wins $175 on his '33' bet: He wins $150

-if the ball lands on a spae that isn't red and isnt 33 he loses both bets, so he loses $30

So for each spin; he either wins $150, wins $20, or loses $30

-probability that he wins $150 is 1/38 or .0263

-probability that he wins $20 is 18/38 or .4737

-probability that he loses $30 is 19/38 or .5000

 

let X = the profit that james makes on the next spin

x P (X=x) x*P(X=x) x^2*P(X=x)
150 .0263 3.945 591.75
20 .4737 9.474 189.48
-30 .5000 -15.000 450.00
sum (sigma) 1.000 -1.581 1231.23

 

u (expected value)= -$1.581

variance = 1228.73044

standard deviation = 35.053

 

FILL IN THE BLANK

 

if you play 2500 times, and

Let, x (x bar)= the mean winnings (or loses) per game. The expected value of x, called ux (expected value of x bar) is ________________________

 

The standard deviation of x (x bar), called 0x (standard deviation of x bar)  is _____________________________

 

this means that for 2500 games, you expect your winnings (or loss) to be 2500 times your average loss per game, which is _____________________.

 

Multiplying the value found for 0x (standard deviation of X (x bar)) by  2500 (the number of games) we find that standard deviation in profit for 2500 games is _________________

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