Jai + Ja₂ = I₁ + 1₂ + 13 Ja₂ = I₁ + 1₂ +13 - IG₁ Jaz = 139.96 20° +131.22 2-36.86 +98.982-45' - 150/-31-79* Jaz = 200 L-20144 A Armature current = 200 A Power factor = (os (20.44) 0.937 lagging Output =(√3 x 3300 x 200 x 0.937) KW Looo 1071 kw How did he get the value inside the circle? Can you explain step by step and clear line please?
Jai + Ja₂ = I₁ + 1₂ + 13 Ja₂ = I₁ + 1₂ +13 - IG₁ Jaz = 139.96 20° +131.22 2-36.86 +98.982-45' - 150/-31-79* Jaz = 200 L-20144 A Armature current = 200 A Power factor = (os (20.44) 0.937 lagging Output =(√3 x 3300 x 200 x 0.937) KW Looo 1071 kw How did he get the value inside the circle? Can you explain step by step and clear line please?
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:Jait Ja₂ = I₁ + 1₂ + 13
Ja₂ = I₁ + 1₂ +13 - IG₁
Jaz
= 139.96 20° +131.22 2-36.86 +98-982-45-150/-31-79*
Jaz
= 2002-20144 A
Armature current = 200 A
Power factor = (os (20.44)
0.937
Output =
bagging
(√3 x 3300 x 200 x 0.937) kw
Looo
1071 kw
How did he get the value inside
the circle? Can you explain step by
step and clear line please?
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