Jacksonville, Florida is due south of Charleston, West Virginia. Find the distance between Jacksonville ( 30°20') and Charleston (38°21'). Assume that the radius of the Earth is 3960 miles. (1) Convert each angle (Jacksonville, Fl and Charleston, WV) in decimal degree (round to 3 decimal places). (2) Find the value of 0. And (3) find the distance between Jacksonville and Charleston to the nearest mile. 1) Decimal degree (round to 3 decimal places) Jacksonville, Fl: Charleston, WV: 2) 0 = O 3) The distance between the two cities is miles.

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Jacksonville, Florida is due south of Charleston, West
Virginia. Find the distance between Jacksonville (
30°20') and Charleston (38°21'). Assume that the
radius of the Earth is 3960 miles. (1) Convert each
angle (Jacksonville, Fl and Charleston, WV) in decimal
degree (round to 3 decimal places). (2) Find the value
of 0. And (3) find the distance between Jacksonville
and Charleston to the nearest mile.
1) Decimal degree (round to 3 decimal places)
Jacksonville, Fl:
Charleston, WV:
2) 0 =
3) The distance between the two cities is
miles.
Transcribed Image Text:Jacksonville, Florida is due south of Charleston, West Virginia. Find the distance between Jacksonville ( 30°20') and Charleston (38°21'). Assume that the radius of the Earth is 3960 miles. (1) Convert each angle (Jacksonville, Fl and Charleston, WV) in decimal degree (round to 3 decimal places). (2) Find the value of 0. And (3) find the distance between Jacksonville and Charleston to the nearest mile. 1) Decimal degree (round to 3 decimal places) Jacksonville, Fl: Charleston, WV: 2) 0 = 3) The distance between the two cities is miles.
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