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J 1. Fin Find 2x³ (6 + x) dx TU

J 1. Fin Find 2x³ (6 + x) dx TU

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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62. answer question 1 only do like this example

Example 8: Solution: Find x²√4 + x dx Let u 4 + X du dx U-4 (u - 4)² u² 8u + 16 (u² - 8u + 16) u du (u - 8u³ + 16u³) du 8u5/2 16u¹2 + + C Sx²√4 + x dx Example 9: Solution: Find Let u xx X X x² X = = 11 11 11 du = dx = = X = X = uz 7 2 2²/(4 + x)²/2² - dx = x² + 1 12:1 T NIGE NIWE x - 1 u + 1 (u + 1)² u² + 2u + 1 2, u = 5, U = 1 11 2-1 LO 16 5 4 + x ³² +33 (4 + x)² + 0
Transcribed Image Text:Example 8: Solution: Find x²√4 + x dx Let u 4 + X du dx U-4 (u - 4)² u² 8u + 16 (u² - 8u + 16) u du (u - 8u³ + 16u³) du 8u5/2 16u¹2 + + C Sx²√4 + x dx Example 9: Solution: Find Let u xx X X x² X = = 11 11 11 du = dx = = X = X = uz 7 2 2²/(4 + x)²/2² - dx = x² + 1 12:1 T NIGE NIWE x - 1 u + 1 (u + 1)² u² + 2u + 1 2, u = 5, U = 1 11 2-1 LO 16 5 4 + x ³² +33 (4 + x)² + 0
TUTORIAL 62 1. Find Find f 2x² (6 + xy dx Use an appropriate substitution to find √√x + 3 dx 2. = 2x - 1 as a substitution to solve the integral x 3. Use u² = 2 4. Using suitable substitution, evaluate SVETO dx X² + 1 5. By using an appropriate substitution, evaluate Answers: (1.) 16 + X²) - (6 + x² ) + 0 (6 C 7 5/2 3/2 C (x² + 1)²-(x² + 3)² + c 2. 5 3/2 5/12 - (2x - 1)^² + (2x − 1)² + c C 3. 6 10 4. 19.7125 1 1 - 1 + In 2 5. परेक x(1 + In
Transcribed Image Text:TUTORIAL 62 1. Find Find f 2x² (6 + xy dx Use an appropriate substitution to find √√x + 3 dx 2. = 2x - 1 as a substitution to solve the integral x 3. Use u² = 2 4. Using suitable substitution, evaluate SVETO dx X² + 1 5. By using an appropriate substitution, evaluate Answers: (1.) 16 + X²) - (6 + x² ) + 0 (6 C 7 5/2 3/2 C (x² + 1)²-(x² + 3)² + c 2. 5 3/2 5/12 - (2x - 1)^² + (2x − 1)² + c C 3. 6 10 4. 19.7125 1 1 - 1 + In 2 5. परेक x(1 + In
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