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- Exercise: The average life of a stove manufactured by GE is 15 years with a s.d. of 2.5 years. (d) Calculate the 96th percentile (e) What percentage of stoves will last between 16 and 20 years?9:10 PM Thu Oct 12 030 35 0 40 045 050 Remix Assuming 90% of adults watch TV every day. In a group of 50 rando mly selected adults, How many adults you expect to watch TV every day do 09 MoonChildNat Today at 7:01 PM React 25% ...Answer.
- The number of dollars a round trip plane ticket costs from North America to Europe is normally distributed with a mean of $1,780 and a standard deviation of $335. What is the probability a randomly selected ticket costs between $775 and $2,785? Enter your answer in decimal form. For example. 75% should be entered as 0.75Please i needs these two. Help me2 Find the abpolute celatia /. 2ongs s % e in when Ond ZA=0:666
- Highway engineers use f(x) = (0.905)* to estimate the likelihood, or probability, that no vehicle will enter a particular intersection within an interval of x seconds. Construct a table of f(x) = (0.905)* starting at x = 0 and incrementing by 10, until x = 50. a. Evaluate f(1) and interpret the result. b. For a time interval of what length is there only a 2% chance that no cars will enter the intersection?The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is 31 hours and the median is 27.2hours. Twenty-four of the families in the sample turned on the television for 16 hours or less for the week. The 8th percentile of the data is 16 hours. Based on the given information, determine if the following statement is true or false. The first quartile is less than 16 hours.min {X1, X2}. %3D Suppose that X1, X2 are iid, and X1 Exp(2). Find the distribution of X(1)
- P(-0.34The 2010 U.S. Census found the chance of a household being a certain size. The data is in the pmf below ("Households by age," 2013). Let X be the number (size) in a household. E(X) = k·P(X = k) 7 (or more) P(X=k) 0.267 0.336 0.158 0.137 0.063 0.024 0.015 k 1 2 3 5 6 a) The probability of a household size being more than 5, P(X > 5) = % b) In the long run, we are expected to see a household size of, E(X)= on average. Round answer to three decimal places. c) The probability that the size of a household is equal to two is %. d) The probability of a household size being three OR six is %.How do I solve for b?SEE MORE QUESTIONS