Please Solve the buoyant force and Specific Gravity of Buoyant. Show complete solution IV.CALCULATION1. BuoyancyWg = BF – WwBF = y x V,Where:W. =weight of the specimenweight of the plumb bob/weightsBF = buoyant forceY =V. = submerged volume of the specimenunit weight of the liquid/waterV.DATA, RESULTS, AND COMPUTATIONTable 5.1 BuoyancyHeight of Wood - 0.299mCross-SectionalDepthSubmerged(m)SpecificGravity ofBuoyArea ofTrialWeights (N)BFSpecimen(m^2)13.950.003450.18523.850.003450.17634.020.003450.190

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IV. CALCULATION 1. Buoyancy We = BF - Ww BF = y x V, Where: W. - weight of the specimen w. = weight of the plumb bob/weights BF - buoyant force Y - unit weight of the liquid/water v. - submerged volume of the specimen V. DATA, RESULTS, AND CcOMPUTATION Table 5.1 Buoyancy Height of Wood - 0.299m Cross-Sectional Area of Specimen (m^2) Depth Submerged Specific Gravity of Buoy Trial Weights (N) BF (m) 3.95 0.00345 0.185 0.176 0.190 0.00345 3.85 4.02 3 0.00345 123

IV. CALCULATION 1. Buoyancy We = BF - Ww BF = y x V, Where: W. - weight of the specimen w. = weight of the plumb bob/weights BF - buoyant force Y - unit weight of the liquid/water v. - submerged volume of the specimen V. DATA, RESULTS, AND CcOMPUTATION Table 5.1 Buoyancy Height of Wood - 0.299m Cross-Sectional Area of Specimen (m^2) Depth Submerged Specific Gravity of Buoy Trial Weights (N) BF (m) 3.95 0.00345 0.185 0.176 0.190 0.00345 3.85 4.02 3 0.00345 123

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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