(iv) (4D2 - 4DD + Du = (v) (D² - 3DD + 2D)u = e* + sin (x- 2y) = 16 log (x + 2y)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Kindly solve 4th part and 5th part

19. Find the complete solution of the following PDES:
(ii) (D² + D°²)u
(iii) (D²- DD'- 2D)u = (v – 1)e*
(iv) (4D² - 4DD' + D)u = 16 log (x + 2y)
(v) (D² - 3DD + 2D)u = e +sin (x- 2y)
= Cos px COs gy
%3D
%3D
Transcribed Image Text:19. Find the complete solution of the following PDES: (ii) (D² + D°²)u (iii) (D²- DD'- 2D)u = (v – 1)e* (iv) (4D² - 4DD' + D)u = 16 log (x + 2y) (v) (D² - 3DD + 2D)u = e +sin (x- 2y) = Cos px COs gy %3D %3D
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