It's been a great day of at the top of the 60° slope shown in the figure. At the bottom, a circular arc carries her through a 90° turn, she then launches off a 3 m-high ramp. How far horizontally is her touchdown point from the end of the ramp? new, frictionless snow. Julie starts and 25 m 90° 60 $3.0 m

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### Problem Description

It's been a great day of new, frictionless snow. Julie starts at the top of the 60° slope shown in the figure. At the bottom, a circular arc carries her through a 90° turn, and she then launches off a 3 m-high ramp. How far horizontally is her touchdown point from the end of the ramp?

### Diagram Explanation

- **Slope:** The slope where Julie starts is inclined at an angle of 60° and has a height of 25 meters.
- **Circular Arc:** At the bottom of the slope, there is a circular arc facilitating a smooth transition through a 90° turn.
- **Ramp:** The ramp from which Julie launches is 3 meters high.
- **Trajectory:** The expected path post-launch is shown as a dashed curve illustrating the projectile motion.

The problem asks to find the horizontal distance Julie will cover after launching off the ramp.
Transcribed Image Text:### Problem Description It's been a great day of new, frictionless snow. Julie starts at the top of the 60° slope shown in the figure. At the bottom, a circular arc carries her through a 90° turn, and she then launches off a 3 m-high ramp. How far horizontally is her touchdown point from the end of the ramp? ### Diagram Explanation - **Slope:** The slope where Julie starts is inclined at an angle of 60° and has a height of 25 meters. - **Circular Arc:** At the bottom of the slope, there is a circular arc facilitating a smooth transition through a 90° turn. - **Ramp:** The ramp from which Julie launches is 3 meters high. - **Trajectory:** The expected path post-launch is shown as a dashed curve illustrating the projectile motion. The problem asks to find the horizontal distance Julie will cover after launching off the ramp.
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