Item No: E-101 DESCRIPTION DUTY BTU/HR EQUIPMENT SPECIFICATION SHEET SHELL AND TUBE HEAT EXCHANGER Multi Tube Single Tube Finned Tube SHELL SIDE TUBE SIDE FLUID TOTAL FLOW LBS/HR INLET OUTLET INLET OUTLET LIQUID LBS/HR Specific Gravity VAPOR LBS/HR OPERATING TEMPERATURES "F PRESSURES PSIA VELOCITIES FT/SEC BULK TEMPERATURE "F VISCOSITY •P SPECIFIC HEAT BTU/LB-F THERMAL CONDUCTIVITY BTU/H-FT-"F PSI PRESSURE DROP MATERIAL OF CONSTRUCTION MATERIAL K BTU/H-FT-*F FOULING FACTOR H-FT2-"F/BTU INDIV HEAT TRANSFER COEF BTU/FT2-H-F OVERALL COEFFICIENT BTU/FT2-H-F NUMBER OF SECTIONS AREA PER SECTION TOTAL AREA LMTD BAFFLE TYPE BAFFLE SPACING SHELL DIAMETER INCHES FT2 SCHEDULE FT2 SHELL LENGTH FT TUBE DIAMETER INCH SCHEDULE OR GAUGE BWG TUBE LENGTH FT Perform a preliminary design to cool 125,000 lbs/h of an organic liquid by countercurrent flow of water in a shell and tube exchanger. Available data is listed below: Fluid circulated Total liquid, lb/h Temperature in, °F Temperature out, °F Specific Gravity Viscosity, cP Specific heat, Btu/lb-°F Thermal Cond. Btu/h-ft-°F Fouling factor, h-ft2-°F/Btu Material of Construction Design assumptions to be used: Shell Side Water 208,333 85 100 Tube Side Organic 125,000 200 150 1 @ 93 °F 1.5 @ 175 °F 1.0 @ 93 °F 2.0 @ 175 °F 1 @ 93 °F 0.5 @ 175 °F 0.36 @ 93 °F 0.1 @ 175 °F 0.002 0.002 Stainless steel Carbon steel Tube-side velocity of 5 ft/s Initial assumed tube length of 20 ft Tube passes must be even number - Shell must be 1 pass - Tube pitch to be 15/16 triangular Baffle spacing 。 Minimum spacing = 1/5 shell OD 。 Maximum spacing = shell OD 。 Spacing interval must be multiple of 6" 。 Shell-side velocity must be close to tube-side velocity Maximum percent excess area of 20% as calculated by: o A (required) = Q/ (Uo * ATLM) 。 % excess area = 100%* (actual area - required area)/(required area) If % excess area exceeds 20%, repeat calculations with 18 ft tube length, 16, etc. until % excess is between 0 and 20%. Design strategy: Estimate a preliminary area from the heat balance Choose a tube diameter - Calculate the required number of tubes Calculate the number of tube passes - - Calculate the tube-side coefficient, hi - Calculate the shell-side coefficient, ho - Calculate the overall heat transfer coefficient, Uo - Calculate the % excess area - If excess area is above 20%, decrease tube length by 2 ft and recalculate
Item No: E-101 DESCRIPTION DUTY BTU/HR EQUIPMENT SPECIFICATION SHEET SHELL AND TUBE HEAT EXCHANGER Multi Tube Single Tube Finned Tube SHELL SIDE TUBE SIDE FLUID TOTAL FLOW LBS/HR INLET OUTLET INLET OUTLET LIQUID LBS/HR Specific Gravity VAPOR LBS/HR OPERATING TEMPERATURES "F PRESSURES PSIA VELOCITIES FT/SEC BULK TEMPERATURE "F VISCOSITY •P SPECIFIC HEAT BTU/LB-F THERMAL CONDUCTIVITY BTU/H-FT-"F PSI PRESSURE DROP MATERIAL OF CONSTRUCTION MATERIAL K BTU/H-FT-*F FOULING FACTOR H-FT2-"F/BTU INDIV HEAT TRANSFER COEF BTU/FT2-H-F OVERALL COEFFICIENT BTU/FT2-H-F NUMBER OF SECTIONS AREA PER SECTION TOTAL AREA LMTD BAFFLE TYPE BAFFLE SPACING SHELL DIAMETER INCHES FT2 SCHEDULE FT2 SHELL LENGTH FT TUBE DIAMETER INCH SCHEDULE OR GAUGE BWG TUBE LENGTH FT Perform a preliminary design to cool 125,000 lbs/h of an organic liquid by countercurrent flow of water in a shell and tube exchanger. Available data is listed below: Fluid circulated Total liquid, lb/h Temperature in, °F Temperature out, °F Specific Gravity Viscosity, cP Specific heat, Btu/lb-°F Thermal Cond. Btu/h-ft-°F Fouling factor, h-ft2-°F/Btu Material of Construction Design assumptions to be used: Shell Side Water 208,333 85 100 Tube Side Organic 125,000 200 150 1 @ 93 °F 1.5 @ 175 °F 1.0 @ 93 °F 2.0 @ 175 °F 1 @ 93 °F 0.5 @ 175 °F 0.36 @ 93 °F 0.1 @ 175 °F 0.002 0.002 Stainless steel Carbon steel Tube-side velocity of 5 ft/s Initial assumed tube length of 20 ft Tube passes must be even number - Shell must be 1 pass - Tube pitch to be 15/16 triangular Baffle spacing 。 Minimum spacing = 1/5 shell OD 。 Maximum spacing = shell OD 。 Spacing interval must be multiple of 6" 。 Shell-side velocity must be close to tube-side velocity Maximum percent excess area of 20% as calculated by: o A (required) = Q/ (Uo * ATLM) 。 % excess area = 100%* (actual area - required area)/(required area) If % excess area exceeds 20%, repeat calculations with 18 ft tube length, 16, etc. until % excess is between 0 and 20%. Design strategy: Estimate a preliminary area from the heat balance Choose a tube diameter - Calculate the required number of tubes Calculate the number of tube passes - - Calculate the tube-side coefficient, hi - Calculate the shell-side coefficient, ho - Calculate the overall heat transfer coefficient, Uo - Calculate the % excess area - If excess area is above 20%, decrease tube length by 2 ft and recalculate
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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