Item 4 (Eigure 1)A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. The battery is removed, and then a dielectric material with dielectric constant K is inserted into the capacitor, filling the space between the plates. Finally, the capacitor is fully discharged through a resistor (which is connected across the capacitor terminals). Figure < 1 of 2 > Part A Find U₂, the the energy dissipated in the resistor. Express your answer in terms of U and other given quantities. View Available Hint(s) U₂ = Submit ▾ Part B U₂ = IΨΕΙ ΑΣΦ Submit IVE| ΑΣΦ. 1 → Consider the same situation as in the previous part, except that the charging battery remains connected while the dielectric is inserted (Figure 2) The battery is then disconnected and the capacitor is discharged. For this situation, what is Ur. the energy dissipated in the resistor? Express your answer in terms of U and other given quantities. ▸ View Available Hint(s) Provide Feedback www ? < 4 of 15 > DANC ? Review Next >

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter27: Capacitors And Batteries
Section27.3: Batteries
Problem 27.5CE: A large parallel-plate capacitor is attached to a battery that has terminal potential (Fig....
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Item 4
(Figure 1)A parallel-plate vacuum capacitor is connected to a battery and
charged until the stored electric energy is U. The battery is removed, and
then a dielectric material with dielectric constant K is inserted into the
capacitor, filling the space between the plates. Finally, the capacitor is fully
discharged through a resistor (which is connected across the capacitor
terminals).
Figure
1 of 2
Part A
Find U₁, the the energy dissipated in the resistor.
Express your answer in terms of U and other given quantities.
► View Available Hint(s)
- ΑΣΦ
U₁ =
Submit
Part B
U₁ =
Submit
Provide Feedback
?
Consider the same situation as in the previous part, except that the charging battery remains connected while the dielectric is inserted. (Figure 2) The battery is then disconnected and
the capacitor is discharged. For this situation, what is U₁, the energy dissipated in the resistor?
Express your answer in terms of U and other given quantities.
► View Available Hint(s)
—| ΑΣΦ
<
?
4 of 15
Review
Next >
Transcribed Image Text:Item 4 (Figure 1)A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. The battery is removed, and then a dielectric material with dielectric constant K is inserted into the capacitor, filling the space between the plates. Finally, the capacitor is fully discharged through a resistor (which is connected across the capacitor terminals). Figure 1 of 2 Part A Find U₁, the the energy dissipated in the resistor. Express your answer in terms of U and other given quantities. ► View Available Hint(s) - ΑΣΦ U₁ = Submit Part B U₁ = Submit Provide Feedback ? Consider the same situation as in the previous part, except that the charging battery remains connected while the dielectric is inserted. (Figure 2) The battery is then disconnected and the capacitor is discharged. For this situation, what is U₁, the energy dissipated in the resistor? Express your answer in terms of U and other given quantities. ► View Available Hint(s) —| ΑΣΦ < ? 4 of 15 Review Next >
Figure
334
< 2 of 2
Transcribed Image Text:Figure 334 < 2 of 2
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