Item 1. At a height of 20 m, an arrow shoots an arrow vertically upwards at a speed of 180 km/hr. Calculate the height 6 at which the arrow can go up, h maximum from the ground, and find the time: ascending, descending of the ball. Archer (Air resistance is not taken and the earth's value is constant, to
Item 1. At a height of 20 m, an arrow shoots an arrow vertically upwards at a speed of 180 km/hr. Calculate the height 6 at which the arrow can go up, h maximum from the ground, and find the time: ascending, descending of the ball. Archer (Air resistance is not taken and the earth's value is constant, to
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Transcribed Image Text:Item 1. At a height of 20 m, an arrow shoots an arrow vertically upwards at a speed of 180 km/hr. Calculate the height 6 at which the arrow can go up, h
maximum from the ground, and find the time: ascending, descending of the ball. Archer (Air resistance is not taken and the earth's value is constant,
equal
to
1
9.81 g m/s) 1) V = 2) vs + at, 3) * = * + 245 - 50), 4) 3 = 50 ++;
Expert Solution
Step 1
Arrow is sent vertically upwards from the height of 20 m from ground
And velocity of arrow =180km/Hr
=180×5/18 m/s = 50 m/s
So there will be a point where arrow will stop
And from third equation of motion
V^2=u^2 - 2*g*h
Where V final velocity of arrow will be zero g=9.8 m/s^2
u^2=2*g*h
(50)^2 =2*9.8*h so h= 128 meters
But from ground it will go 20+h=148 meters upwards so arrow will reac 148 meter height above ground.
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