Understanding Atmospheric Pressure Changes with Altitude**Scenario:**It was reported that on a particular day in Saint Cloud, MN, the atmospheric pressure was 94,500 Pa at the ground level. A student wants to measure the pressure using a barometer at 2 meters above the ground level. To calculate the expected pressure in Pascals (Pa), consider that the atmospheric pressure decreases by 11.5 Pa per meter of altitude increase.**Question:**How much pressure in Pa is the student expected to find at 2 meters above ground level?**Given Data:**- Ground Level Pressure: 94,500 Pa- Altitude Difference: 2 meters- Pressure Decrease Rate: 11.5 Pa/meter**Calculation:**1. Calculate the total pressure decrease over 2 meters.\[ \text{Total Pressure Decrease} = \text{Altitude Difference} \times \text{Pressure Decrease Rate} \]\[ \text{Total Pressure Decrease} = 2 \, \text{meters} \times 11.5 \, \text{Pa/meter} = 23 \, \text{Pa} \]2. Subtract the total pressure decrease from the ground level pressure to find the pressure at 2 meters above ground.\[ \text{Pressure at 2 meters} = \text{Ground Level Pressure} - \text{Total Pressure Decrease} \]\[ \text{Pressure at 2 meters} = 94,500 \, \text{Pa} - 23 \, \text{Pa} = 94,477 \, \text{Pa} \]**Expected Pressure:**The student is expected to find 94,477 Pa at 2 meters above the ground level.

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It was reported that was 94,500 Pa at the above the ground lev

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Question

<strong>Understanding Atmospheric Pressure Changes with Altitude</strong>

**Scenario:**
It was reported that on a particular day in Saint Cloud, MN, the atmospheric pressure was 94,500 Pa at the ground level. A student wants to measure the pressure using a barometer at 2 meters above the ground level. To calculate the expected pressure in Pascals (Pa), consider that the atmospheric pressure decreases by 11.5 Pa per meter of altitude increase.

**Question:**
How much pressure in Pa is the student expected to find at 2 meters above ground level?

**Given Data:**
- Ground Level Pressure: 94,500 Pa
- Altitude Difference: 2 meters
- Pressure Decrease Rate: 11.5 Pa/meter

**Calculation:**
1. Calculate the total pressure decrease over 2 meters.
\[ \text{Total Pressure Decrease} = \text{Altitude Difference} \times \text{Pressure Decrease Rate} \]
\[ \text{Total Pressure Decrease} = 2 \, \text{meters} \times 11.5 \, \text{Pa/meter} = 23 \, \text{Pa} \]

2. Subtract the total pressure decrease from the ground level pressure to find the pressure at 2 meters above ground.
\[ \text{Pressure at 2 meters} = \text{Ground Level Pressure} - \text{Total Pressure Decrease} \]
\[ \text{Pressure at 2 meters} = 94,500 \, \text{Pa} - 23 \, \text{Pa} = 94,477 \, \text{Pa} \]

**Expected Pressure:**
The student is expected to find 94,477 Pa at 2 meters above the ground level.

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