It was observed that around 90% of a certainceramic sample fractures within 5 hours oncesubjected to a certain amount of stress.Suppose that the situation can be modeled asan exponential distribution, estimate theprobability that fracture will occur within threehours.O 0.50O 0.15O 0.25O 0.75none of these

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Answered: It was observed that around 90% of a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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l Globe 8:46 AM 92% A docs.google.com 2.b.The IQ scores of children in a special education class are normally distributed with µ = 95 and o = 10. What is the probability that a child has an IQ score above 120? * 0.9938 0.6200 0.9940 0.0062 This is a required question 2.c.The IQ scores of children in a special education class are normally distributed with µ = 95 and o = 10. What is the chances that a child has an IQ score of 90? * 0.3085 0.6915 1.00 0.3080
A certain make of car tyre can be safely used for 25 000km on average before it is replaced. The makers guarantee to pay compensation to anyone whose tyre does not last for 22 to 0km. They expect 7.5% of all tyres sold to qualify for compensation. Assuming that the distance X travelled before a tyre is replaced has a normal probability distribution. Use this information to answer questions 10-11. 11. Find the standard deviation of X.
Question 1
0 Question 18: Based on historical data, your manager believes that 29% of the company's orders come from first- time customers. A random sample of 150 orders will be used to estimate the proportion of first- time customers. What is the probability that the sample proportion is between 0.2 and 0.31? Note: You should carefully round any z-values you calculate to 4 decimal places.
Which of the following are true when considering the probability of spinning a multiple of 5 on an equal section spinner with numbers 1-20? which apply. a. P(A) = ⅕ b. n(S) = 20 c. n(A) = 4 d. n(A’) = 16 e. P(A) = 20% f. A = {5,10,15,20} g. P(A) = 4/20 h. P(A’) = ⅘ i. P(A’) = 0.8 j. S is all numbers between 1 and 20 inclusive
The Gunn General Store is interested in developing a model to predict the probability that the clerk is busy and a customer has to wait. Using a single service model, a Poison distribution for customer arrivals, and service times that are exponentially distributed, the company has determined that λ=13 and μ=16. What is the probability that the clerk is busy and a customer has to wait? a. 0.23 b. 0.81 c. 0.19 d. 0.77
Question 9 Consider a Binomial Distribution of B(2,323, 0.294) Find the Expected value for the number of successes (or mean) for the probability density function.
KINDLY ANSWER THE LAST ITEM (c)
QUESTION 1 Let X be a normal random variable with mean u = 68 and standard deviation o =11. What is the probability that Xwill be (a). more than 79? (b). between 57 and 79? (c), less than 46?
Below is the life table of a population of waterbuck. What is the probability that an individual in stage 2 will survive to stage 3 (give your answer to three decimal places)? Stage 0 1 2 3 4 5 ax 50 39 25 20 11 4 Answer: 0.200 1.00 0.78 0.50 0.40 0.22 0.08 Ix dx 11 14 5 9 7 4 Probability of survival = lx+1/lx The correct answer is: 0.8 0.220 0.359 0.200 0.450 0.636 1.000 qx X
GLA2.3
15. During a recent period of high unemployment, hundreds of thousands of drivers dropped their automobile insurance. Sample data representative of the national automobile insur- ance coverage for individuals 18 years of age and older are shown here. b. C. Age 18 to 34 35 and over 60 Automobile Insurance Yes 1500 1900 a. Develop a joint probability table for these data and use the table to answer the remaining questions. No 340 260 What do the marginal probabilities tell you about the age of the U.S. population? What is the probability that a randomly selected individual does not have automobile insurance coverage? d. If the individual is between the ages of 18 and 34, what is the probability that the individual does not have automobile insurance coverage? e. If the individual is age 35 or over, what is the probability that the individual does not have automobile insurance coverage? f. If the individual does not have automobile insurance, what is the probability that the individual is…

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