It was hypothesized that there will be a difference in average test score in chemistry class between high schoolers who watched Breaking Bad (G1) and high schoolers who did not watch Breaking Bad (G2). Calculate and use the appropriate statistical test to analyze the below. Alpha criteria is set at 0.01. Watched Breaking Bad 99 Did Not Watch Breaking Bad 90 82 85 82 86 79 91 98 97 94 86 92 83 93 81 n = 8 M = 93.75 SS = 127.5 n = 8 M = 83.50 SS = 82 Is this a one-tailed or two-tailed hypothesis? What is your degrees of freedom?
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- The life span in Honolulu is approximately normally distributed. The mean life span is 77 years. A foreign newspaper claims that the mean lifespan for Honolulu residents is less than 77 years. You randomly select a sample of 20 obituary notices in a Honolulu newspaper. The table below shows the data collected (in years). 72 68 81 93 56 19 78 94 83 84 77 69 85 97 75 71 86 47 66 27 Test the foreign newspaper's claim using a = 0.01. There is enough evidence to reject the null hypothesis. The claim is true. There is enough evidence to reject the null hypothesis. The claim is false. There is not enough evidence to reject the null hypothesis. The claim is probably true. There is not enough evidence to reject the null hypothesis. The claim is probably false.An ANOVA is used to compare the mean GPA of the following groups of students.Two popular brands of tires for tractor-trailers are the Puma and the Eternal. Salma is a buyer for a major shipping company and wants to determine if there is any difference between the two brands of tire in the mean distance (in thousands of km) driven on them before they need to be replaced. In the company's testing lab, Salma tests a random sample of 14 Puma tires and a random sample of 15 Eternal tires. (These samples are chosen independently.) For the Puma tires, the sample mean distance (in thousands of km) until they would need to be replaced is 54.71 with a sample variance of 5.95. For the Eternal tires, the sample mean distance (in km) until they would need to be replaced is 50.21 with a sample variance of 37.75. Assume that the two populations of distances driven are approximately normally distributed. Can Salma conclude, at the 0.05 level of significance, that there is a difference between the population mean of the distances (in thousands of km) driven on Puma tires before…
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- Modern medical practice tells us not to encourage babies to become too fat. Is there a positive correlation between the weight x of a 1-year old baby and the weight y of the mature adult (30 years old)? A random sample of medical files produced the following information for 14 females. x (lb) 19 24 25 23 20 15 25 21 17 24 26 22 18 19 y (lb) 126 126 125 124 130 120 145 130 130 130 130 140 110 115 In this setting we have Σx = 298, Σy = 1781, Σx2 = 6492, Σy2 = 227,603, and Σxy = 38,105. f) Find Se. (Round your answer to two decimal places.)Se = (g) Find a 95% confidence interval for weight at age 30 of a female who weighed 21 pounds at 1 year of age. (Round your answers to two decimal places.) lower limit lb upper limit lb (h) Test the claim that the slope ? of the population least-squares line is positive at the 1% level of significance. (Round your test statistic to three decimal places.) t =A researcher wants to know if there is a difference between the mean amount of sleep that people get for various types of employment status. The table below shows data that was collected from a survey. Full Time Worker Part Time Worker Unemployed 6 6 7 5 6 7 8 9 9 7 6 8 8 8 8 8 8 8 6 6 8 8 7 6 9 Assume that all distributions are normal, the three population standard deviations are all the same, and the data was collected independently and randomly. Use a level of significance of α=0.01α=0.01.H0: μ1=μ2=μ3H0: μ1=μ2=μ3H1:H1: At least two of the means differ from each other. For this study, we should use Select an answer 2-PropZTest 2-PropZInt 1-PropZInt 2-SampTInt 1-PropZTest T-Test χ²-Test ANOVA χ²GOF-Test TInterval 2-SampTTest The test-statistic for this data = (Please show your answer to 3 decimal places.) The p-value for this sample = (Please show your answer to 4 decimal places.) The p-value is Select an answer less than (or equal to) alpha greater…Fertilizer: A new type of fertilizer is being tested on a plot of land in an orange grove, to see whether it increases the amount of fruit produced. The mean number of pounds of fruit on this plot of land with the old fertilizer was 381 pounds. Agriculture scientists believe that the new fertilizer may increase the yield. State the appropriate null and alternate hypotheses. Answer the following question.
- Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? 143 140 141 136 133 Right arm Left arm 180 174 192 140 144 In this example, . is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 O B. Ho: Hd #0 0 = Prt :H O D. Ho: Hd =0 H O C. Ho: Ha 0 Identify the test statistic. t%3D (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test?…The data below shows the SAT scores of 30 students at Martin Luther King High School in Florida. 1561 1554 1536 1531 1523 1518 1515 1511 1506 1500 1499 1493 1490 1489 1485 1482 1482 1479 1477 1466 1453 1448 1439 1432 1423 1421 1413 1407 1394 1388 a. Test the hypothesis that mean is less than 1500. Use the 1% level of significance. b. Would your conlcusion change at the 10% level of significance? Show all stepsListed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left arm 151 136 120 134 134 181 174 180 156 138 In this example, Ha is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Hd = 0 O B. Ho: Hd 0 O C. Ho: Hd = 0 O D. Ho: Hd 0 H1: Ha>0