iT Q.9: For the circuit shown, if (it=5+3sin@t+1.5sin2@t) Amp. Write the: eT J22 1. Non-sinusoidal current equation in the capacitance. 2. Non-sinusoidal voltage equation of (e) applied to the circuit. -J8 0=500rad/sec (Ans.: ic=0.707 sin(@t+ 135°)+sin(2@t+ 90°) Amp e=7.07sin(@t+819°) +7.2sin (2@t+56.31°) V) &
iT Q.9: For the circuit shown, if (it=5+3sin@t+1.5sin2@t) Amp. Write the: eT J22 1. Non-sinusoidal current equation in the capacitance. 2. Non-sinusoidal voltage equation of (e) applied to the circuit. -J8 0=500rad/sec (Ans.: ic=0.707 sin(@t+ 135°)+sin(2@t+ 90°) Amp e=7.07sin(@t+819°) +7.2sin (2@t+56.31°) V) &
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![iT
Q.9: For the circuit shown, if (iT=5+3sin@t+1.5sin2@t) Amp.
eT
Write the:
J22
1. Non-sinusoidal current equation in the capacitance.
2. Non-sinusoidal voltage equation of (e) applied to the
circuit.
0=500rad/sec
(Ans.: ic=0.707sin(@t+135°)+sin(2@t+90°)
Amp
&
e=7.07sin(@t+819°)+7.2sin (2@t+56.31°) V)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb3bde3c-2a30-4da1-8d80-3736b7ed2aa1%2F0209d91f-2816-433a-8628-9f740a55b5e3%2Fe7t2es_processed.jpeg&w=3840&q=75)
Transcribed Image Text:iT
Q.9: For the circuit shown, if (iT=5+3sin@t+1.5sin2@t) Amp.
eT
Write the:
J22
1. Non-sinusoidal current equation in the capacitance.
2. Non-sinusoidal voltage equation of (e) applied to the
circuit.
0=500rad/sec
(Ans.: ic=0.707sin(@t+135°)+sin(2@t+90°)
Amp
&
e=7.07sin(@t+819°)+7.2sin (2@t+56.31°) V)
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