it means the reverse reaction will proceed to form more reactants O None of the above are true. QUESTION 21 At 1400 K, the value of Ke for 2 HBr (g) 12 (g) + Br2 (g) is 1.5-10-5. What is the equilibrium concentration of 112 in a 1.00 liter container that initially held 0.10 mol HBr and 0.15 mol of Brg? O a.0.0 M O b.0.10 M Oc 1.5 x 10-5 M O d. 1.0 x 10-6 M O e. 0.75 M

it means the reverse reaction will proceed to form more reactants O None of the above are true. QUESTION 21 At 1400 K, the value of Ke for 2 HBr (g) 12 (g) + Br2 (g) is 1.5-10-5. What is the equilibrium concentration of 112 in a 1.00 liter container that initially held 0.10 mol HBr and 0.15 mol of Brg? O a.0.0 M O b.0.10 M Oc 1.5 x 10-5 M O d. 1.0 x 10-6 M O e. 0.75 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For the reaction: 2 IBr(g) qe I2(g) + Br2(g), Kc = 3.57 * 10-3 (150 ̊C), held within a 1.00 L flask If 0.500 M I2 and 0.500 M Br2 are allowed to reach equilibrium, what are the equilibrium concentrations of I2, Br2 and IBr?
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At equilibrium, the concentrations in this system were found to be (N,] [0,] 0.200 M and (NO) = 0.400 M. N, (g) + 0,) = 2 NO(g) If more NO is added, bringing its concentration to 0,700 M, what will the final concentration of NO be after equilibrium is re-established? 0.6 ME Incorrect
Calculate the concentration of O2, if at equilibrium there are 0.552 mole of C2H4, 0.994 mole of CO2, 0.283 mole of H:O in a 0.585 L container and K= 7.45 _C:H«(g) + 30:(g) = 2CO:(g) + 2H20(g) *