% Given data t = [0 15 30 45 60 75 90]; % theta values in degrees S = [0 0.5 0.86603 1 0.86603 0.5 0]; % sin(2*theta) values % Number of intervals (n) n = length(t) - 1; % Simpson's 3/8 rule requires the number of intervals (n) to be a multiple of 3 if mod(n, 3) = 0 end error('The number of intervals (n) must be a multiple of 3 for Simpson''s 3/8 rule'); % Step size (h) h (t(end) t(1)) / n; = - % Calculate the integral using Simpson's 3/8 rule integral = s(1) + s(end); for i = 2:3:n-1 end integral = integral + 3 * s(i) + 3 * s(i+1) + 2 * s(i+2); integral = integral + 3 s(n); % Final multiplication by 3h/8 integral = (3 * h / 8) * integral; % Display the result disp(['The area under the curve from 0 to ↓ degrees is: ', num2str(integral), ' deg']); It looks like you need help with MATLAB code to apply Simpson's 3/8 rule for numerical integration to determine the area under a curve. I'll help you correct and explain your MATLAB code. The Simpson's 3/8 rule for integration is given by: So f(x) dx ≈ ³h [f(a)+3f(a+h) +3ƒ(a+2h) + f(b)]
% Given data t = [0 15 30 45 60 75 90]; % theta values in degrees S = [0 0.5 0.86603 1 0.86603 0.5 0]; % sin(2*theta) values % Number of intervals (n) n = length(t) - 1; % Simpson's 3/8 rule requires the number of intervals (n) to be a multiple of 3 if mod(n, 3) = 0 end error('The number of intervals (n) must be a multiple of 3 for Simpson''s 3/8 rule'); % Step size (h) h (t(end) t(1)) / n; = - % Calculate the integral using Simpson's 3/8 rule integral = s(1) + s(end); for i = 2:3:n-1 end integral = integral + 3 * s(i) + 3 * s(i+1) + 2 * s(i+2); integral = integral + 3 s(n); % Final multiplication by 3h/8 integral = (3 * h / 8) * integral; % Display the result disp(['The area under the curve from 0 to ↓ degrees is: ', num2str(integral), ' deg']); It looks like you need help with MATLAB code to apply Simpson's 3/8 rule for numerical integration to determine the area under a curve. I'll help you correct and explain your MATLAB code. The Simpson's 3/8 rule for integration is given by: So f(x) dx ≈ ³h [f(a)+3f(a+h) +3ƒ(a+2h) + f(b)]
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Don't use ai to answer I will report your answer Solve it Asap with explanation and calculation
![% Given data
t = [0 15 30 45 60 75 90]; % theta values in degrees
S = [0 0.5 0.86603 1 0.86603 0.5 0]; % sin(2*theta) values
% Number of intervals (n)
n = length(t) - 1;
% Simpson's 3/8 rule requires the number of intervals (n) to be a multiple of 3
if mod(n, 3) = 0
end
error('The number of intervals (n) must be a multiple of 3 for Simpson''s 3/8 rule');
% Step size (h)
h (t(end) t(1)) / n;
=
-
% Calculate the integral using Simpson's 3/8 rule
integral =
s(1) + s(end);
for i = 2:3:n-1
end
integral = integral + 3 * s(i) + 3 * s(i+1) + 2 * s(i+2);
integral = integral + 3 s(n);
% Final multiplication by 3h/8
integral = (3 * h / 8) * integral;
% Display the result
disp(['The area under the curve from 0 to ↓ degrees is: ', num2str(integral), ' deg']);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45202855-3e5d-4418-a214-3337cf65b332%2F4ec5a288-ec34-4c02-99aa-a2f540f8fdf4%2Fw4bhdj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:% Given data
t = [0 15 30 45 60 75 90]; % theta values in degrees
S = [0 0.5 0.86603 1 0.86603 0.5 0]; % sin(2*theta) values
% Number of intervals (n)
n = length(t) - 1;
% Simpson's 3/8 rule requires the number of intervals (n) to be a multiple of 3
if mod(n, 3) = 0
end
error('The number of intervals (n) must be a multiple of 3 for Simpson''s 3/8 rule');
% Step size (h)
h (t(end) t(1)) / n;
=
-
% Calculate the integral using Simpson's 3/8 rule
integral =
s(1) + s(end);
for i = 2:3:n-1
end
integral = integral + 3 * s(i) + 3 * s(i+1) + 2 * s(i+2);
integral = integral + 3 s(n);
% Final multiplication by 3h/8
integral = (3 * h / 8) * integral;
% Display the result
disp(['The area under the curve from 0 to ↓ degrees is: ', num2str(integral), ' deg']);
![It looks like you need help with MATLAB code to apply Simpson's 3/8 rule for numerical integration
to determine the area under a curve. I'll help you correct and explain your MATLAB code.
The Simpson's 3/8 rule for integration is given by:
So f(x) dx ≈ ³h [f(a)+3f(a+h) +3ƒ(a+2h) + f(b)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45202855-3e5d-4418-a214-3337cf65b332%2F4ec5a288-ec34-4c02-99aa-a2f540f8fdf4%2Fi3iq0y_processed.jpeg&w=3840&q=75)
Transcribed Image Text:It looks like you need help with MATLAB code to apply Simpson's 3/8 rule for numerical integration
to determine the area under a curve. I'll help you correct and explain your MATLAB code.
The Simpson's 3/8 rule for integration is given by:
So f(x) dx ≈ ³h [f(a)+3f(a+h) +3ƒ(a+2h) + f(b)]
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