Which formula do you use to calculate the total energy stored in the equivalent inductance? 11 ○ WL (t) = v² (t) 2 Leg ○ WL (t) = L²²² (t) ○ WL (t) = Leav² (t) 1 ○ W₁(t) = 1² (t) 2 Leg ○ WL (t) = v² (t) OWL(t) = Lea² (t) ○ WL (t) = Leqv² (t) ○ WL(t) = 1² (t) Leg ○ WL (t) = Leq²² (t) ○ WL (t) = L²² (t) i(t) L₁ m m m L3 L2 LA m -Ob L₁ = 20mH L2 = 50mH L3 = 70mH L4 = 65mH i(t) = 30mA.e
Which formula do you use to calculate the total energy stored in the equivalent inductance? 11 ○ WL (t) = v² (t) 2 Leg ○ WL (t) = L²²² (t) ○ WL (t) = Leav² (t) 1 ○ W₁(t) = 1² (t) 2 Leg ○ WL (t) = v² (t) OWL(t) = Lea² (t) ○ WL (t) = Leqv² (t) ○ WL(t) = 1² (t) Leg ○ WL (t) = Leq²² (t) ○ WL (t) = L²² (t) i(t) L₁ m m m L3 L2 LA m -Ob L₁ = 20mH L2 = 50mH L3 = 70mH L4 = 65mH i(t) = 30mA.e
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question
1.5
![Which formula do you use to calculate the total energy stored in the equivalent inductance?
11
○ WL (t) = v² (t)
2 Leg
○ WL (t) = L²²² (t)
○ WL (t) = Leav² (t)
1
○ W₁(t) = 1² (t)
2 Leg
○ WL (t) = v² (t)
OWL(t) = Lea² (t)
○ WL (t) = Leqv² (t)
○ WL(t) = 1² (t)
Leg
○ WL (t) = Leq²² (t)
○ WL (t) =
L²² (t)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51e7283f-1187-4641-a7dd-756ddc41b628%2Fc86dbcf8-de0e-42f3-84c5-d5748b580130%2Ffcraz2v_processed.png&w=3840&q=75)
Transcribed Image Text:Which formula do you use to calculate the total energy stored in the equivalent inductance?
11
○ WL (t) = v² (t)
2 Leg
○ WL (t) = L²²² (t)
○ WL (t) = Leav² (t)
1
○ W₁(t) = 1² (t)
2 Leg
○ WL (t) = v² (t)
OWL(t) = Lea² (t)
○ WL (t) = Leqv² (t)
○ WL(t) = 1² (t)
Leg
○ WL (t) = Leq²² (t)
○ WL (t) =
L²² (t)
![i(t)
L₁
m m
m
L3
L2
LA
m
-Ob
L₁
= 20mH
L2
= 50mH
L3
= 70mH
L4
= 65mH
i(t)
=
30mA.e](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51e7283f-1187-4641-a7dd-756ddc41b628%2Fc86dbcf8-de0e-42f3-84c5-d5748b580130%2Fbz5n458_processed.png&w=3840&q=75)
Transcribed Image Text:i(t)
L₁
m m
m
L3
L2
LA
m
-Ob
L₁
= 20mH
L2
= 50mH
L3
= 70mH
L4
= 65mH
i(t)
=
30mA.e
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