It is well-known that ∞ Σ4(-1)1+1 1 =πT 2j-1 j=1 and j=1 Compute S1,n ==14(-1)+1 2-1 and S2,n = Σ=16½ for n = 25 (if you use calculator) or n = 100000 (if you use computer) in order to find an approximation of 7. Actually, T3.14159265358979323846264338327950288419716939937510582097494459230781640628620 and 1 = 9.8696044010893586188344909998761511353136994072407906264133493. How many decimal places agree? As a solution of the exercise, provide your computations (if you use calculator) or code (if you use computer).
It is well-known that ∞ Σ4(-1)1+1 1 =πT 2j-1 j=1 and j=1 Compute S1,n ==14(-1)+1 2-1 and S2,n = Σ=16½ for n = 25 (if you use calculator) or n = 100000 (if you use computer) in order to find an approximation of 7. Actually, T3.14159265358979323846264338327950288419716939937510582097494459230781640628620 and 1 = 9.8696044010893586188344909998761511353136994072407906264133493. How many decimal places agree? As a solution of the exercise, provide your computations (if you use calculator) or code (if you use computer).
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 43RE
Related questions
Question
Numerical an

Transcribed Image Text:It is well-known that
∞
Σ4(-1)1+1
1
=πT
2j-1
j=1
and
j=1
Compute S1,n ==14(-1)+1 2-1 and S2,n = Σ=16½ for n = 25 (if you use calculator) or
n = 100000 (if you use computer) in order to find an approximation of 7. Actually,
T3.14159265358979323846264338327950288419716939937510582097494459230781640628620
and
1
= 9.8696044010893586188344909998761511353136994072407906264133493.
How many decimal places agree? As a solution of the exercise, provide your computations (if you
use calculator) or code (if you use computer).
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