It is required to layout a simple curve by deflection angles. The curve is to connect two tangents with an intersection angle of 32° and a radius of 240m. Compute the deflection angles to each full stations in the curve, if the transit is set-up at PC which is station 5+767.2. What is the stationing of the PT? Sta Occ Sta Obs Deflection Angle Remarks 5+767.2 5+780 1°31'30" 1 5+800 3°54'30" 2 5+820 6°17'30" 3 5+8400 4 5+860 5+880 5+900 7 5+901.47 16° PT 6.

Q: The tangents for a D = 4º30' circular curve (arc definition) meet at PI Sta 34+18.19 and the…

A: Degree of Curve = 4°30'PI of Station = 34+18.19Deflection angle (I) = 25°48'

Q: wo straight tangents of a two-line highway intersect at point B. The tangents have azmuths of 270…

A: azmuths- 2700 and 1100  Radius - 7300 ft To find - a)the tangent lengths b)the length of curve c) PI…

Q: For the PI Inaccessible problem: Sta. X = 70+00.00, XY =800.00 ft, angle x = 35°00'00", angle y =…

A: Sta. X = 70+00.00XY = 800.00 ftAngle X = 35Angle Y = 30The radius for the simple curve = 1000 ftTo…

Q: SITUATION. The long chord of a compound curve is equal to 250 meters. The PC this curve is at STA…

A:

Q: Calculate the radius of the simple curve when the offset distance of the simple curve from P.T. to…

A:

Q: #9dmul jabutz STAPI=135+ 76.45 4. There is a curve with a Back Tangent with a bearing of S 30° E and…

A: Bearing of back tangent = S30oE Bearing of forward tangent = S85oE Degree of curve, D = 10o

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