It is known that X = 1,2,3 and 4 = 1,2,3 are two variables with the probability Mass function p(x=x₁y+y) expressed as p(x,y) which is given as follows: P (1.4) 1 P (2, 1) = 1 P (3.1)= 1 3 P (1,2) Based 1 g P(1,3) O P (212) = 0 р 6 a) Find P(X=X |Y= 1)! b) Find P (Y=y | X= 1)! P (312)= 1 18 P (313) 1 on the probability information above 9 c show that variable X and variable + are not Independent !

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A: It is an important part of statistics. It is widely used.

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