It is known that 10% of all the items produced by a particular manufacturing process are defective. From the very large output of a single day, 900 items were selected at random. Complete parts (a) through (d) below. Click the icon to view the standard normal table of the cumulative distribution function. a. What is the probability that at least 83 of the selected items are defective? P(X2 83) = (Round to four decimal places as needed.) b. What is the probability that between 90 and 107 of the selected items are defective? deslons P(90 sXs 107) = (Round to four decimal places as needed.) 没有找到结果,请点击“更多释义"详细查询 c. What is the probability that between 81 and 103 of the selected items are defective?
It is known that 10% of all the items produced by a particular manufacturing process are defective. From the very large output of a single day, 900 items were selected at random. Complete parts (a) through (d) below. Click the icon to view the standard normal table of the cumulative distribution function. a. What is the probability that at least 83 of the selected items are defective? P(X2 83) = (Round to four decimal places as needed.) b. What is the probability that between 90 and 107 of the selected items are defective? deslons P(90 sXs 107) = (Round to four decimal places as needed.) 没有找到结果,请点击“更多释义"详细查询 c. What is the probability that between 81 and 103 of the selected items are defective?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Transcribed Image Text:It is known that 10% of all the items produced by a particular manufacturing process are defective. From the very large output of a single day, 900 items were selected
at random. Complete parts (a) through (d) below.
Click the icon to view the standard normal table of the cumulative distribution function.
...
a. What is the probability that at least 83 of the selected items are defective?
P(X2 83) =
(Round to four decimal places as needed.)
b. What is the probability that between 90 and 107 of the selected items are defective?
deslons
P(90 sX< 107)= (Round to four decimal places as needed.)
没有找到结果,请点击“更多释义”详细查询
c. What is the probability that between 81 and 103 of the selected items are defective?
Transcribed Image Text:P(90 <Xs 107) = (Round to four decimal places as needed.)
c. What is the probability that between 81 and 103 of the selected items are defective?
P(81 sXS 103) =| (Round to four decimal places as needed.)
d. Without doing the calculations, state which of the ranges of defectives shown below has the highest probability.
90 – 91
87 - 88
95 - 96
92 - 93
96 – 97
Which range below has the highest probability?
O A. 90 - 91
O B. 92 - 93
O C. 96 - 97
O D. 95 - 96
O E. 87 - 88
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