Solve all or dislike It is impossible to increase both the sensitivity function and complementary sensitivityfunction because:There sum is constantO b. Plant characteristics may change with timeAccuracy of parameters are not good enoughO d. Neglected nonlinear characteristics of the plant For the Transfer function:Y(x)U(s) s2 + 3s + 2One of the formations of the vector C in the Diagonal Canonical form is:N+3O. [-3 olOb 12 -1][o -3)O d. (o -2)

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It is impossible to increase both the sensitivity function and complementary sensitivity function because: There sum is constant O b. Plant characteristics may change with time Oe Accuracy of parameters are not good enough Neglected nonlinear characteristics of the plant

It is impossible to increase both the sensitivity function and complementary sensitivity function because: There sum is constant O b. Plant characteristics may change with time Oe Accuracy of parameters are not good enough Neglected nonlinear characteristics of the plant

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

Solve all or dislike

It is impossible to increase both the sensitivity function and complementary sensitivity
function because:
There sum is constant
O b. Plant characteristics may change with time
Accuracy of parameters are not good enough
O d. Neglected nonlinear characteristics of the plant

For the Transfer function:
Y(x)
U(s) s2 + 3s + 2
One of the formations of the vector C in the Diagonal Canonical form is:
N+3
O. [-3 ol
Ob 12 -1]
[o -3)
O d. (o -2)

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