It is important in the last two theorems that the domain be simply connected. So this by showing that when U = {z :1< |z| < 3} that the function f(z) = z has no analytic logarithm. Hint: If e(2) z, then take a derivative to get eg(3) g'(2) = 1. This 1 implies g'(z) = e¬9(z) = ±. Let y be the circle |2| = 2. Then by the calculation we have just done 2ni. (you may assume that f, many times). Now explain why 2ni as we have done this calculation ) dz = 0 which gives a contradiction.
It is important in the last two theorems that the domain be simply connected. So this by showing that when U = {z :1< |z| < 3} that the function f(z) = z has no analytic logarithm. Hint: If e(2) z, then take a derivative to get eg(3) g'(2) = 1. This 1 implies g'(z) = e¬9(z) = ±. Let y be the circle |2| = 2. Then by the calculation we have just done 2ni. (you may assume that f, many times). Now explain why 2ni as we have done this calculation ) dz = 0 which gives a contradiction.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:It is important in the last two theorems that
the domain be simply connected. So this by showing that when U =
{z :1< |z| < 3} that the function f(z) = z has no analytic logarithm.
Hint: If e9(2)
= z, then take a derivative to get e9(=)gʻ(z) = 1. This
1
implies g'(2) = e-9(2)
calculation we have just done
Let y be the circle |2| = 2. Then by the
dz
(2) dz
2ni.
(you may assume that ,
many times). Now explain why
= 2ri as we have done this calculation
'(z) dz = 0
which gives a contradiction.
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